Question

An electron as q = 1.602 * 10-19 C is placed .03m away from spherical object with a net charge of -7.2 C.

Answer 1

Answer:

See explanation

Explanation:

The electric force exerted on the electron is given by Coulomb's law;

F= KqQ/r^2

F= force on the electron

K= constant of Coulomb's law

q= charge on the electron

Q=charge on the spherical object

r= distance between the charges

F= 9×10^9 × -1.602 × 10^-19 × (-7.2)/(0.03)^2

F= 103.8 × 10^-10/9×10^-4

F= 11.53 ×10^-6

F= 1.153 ×10^-5 N

The force in this case is repulsive

E= F/q

E= 1.153 ×10^-5 N/ 1.602 * 10-19 C

E= 0.719 × 10^14

E= 7.19 × 10^13 NC-1

The electro field around the electron is very strong.

c)

V= Kq/r

V= 9×10^9 × 1.602 × 10^-19/0.001

V= 14418 × 10^-10

V=1.4418 ×10^-6 V

W= qV

W= 1.602×10^-19 C × 1.4418 ×10^-6 V

W= 2.31 ×10^-25 J

Replacing the electron with a positron

F= 9×10^9 × 1.602 × 10^-19 × (-7.2)/(0.03)^2

F= 103.8 × 10^-10/9×10^-4

F= 11.53 ×10^-6

F= -1.153 ×10^-5 N

The force in this case is attractive