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nexus9112 [7]
3 years ago
12

What is the approximate geometry around each oxygen atom

Chemistry
1 answer:
AnnyKZ [126]3 years ago
7 0

Answer:

correct option: A. tetrahedral

Explanation:

when we talk about hydrogen bonding in water due to oxygen then need to check the number of lone pair available for hydrogen bonding because hydrogen bond form between lone pair of oxygen and hydrogen of other water molecule so there are two lone pair which forms hydrogen bond and there are also two other covalent bond with hydrogen of same molecule so total number is 4 it means they will form a tetrahedral geometry

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30 its ASAP!!!! What is the volume, in liters, occupied by 0.485 moles of Oxygen gas at 23.0 oC and 0.980 atm?
USPshnik [31]
Use the universal gas formula

PV=nRT
where
P=pressure ( 0.980 atm)
V=volume (L)
T=temperature ( 23 ° C = 23+273.15 = 296.15 ° K)
n=number of moles of ideal gas (0.485 mol)
R=universal gas constant = <span>0.08205 L atm / (mol·K)

Substitute values,
Volume, V (in litres)
=nRT/P
=0.485*0.08205*296.15/0.980
= 12.0256 L
= 12.0 L (to three significant figures)

</span>
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3 years ago
In a chemical change, the substance that you end up with is the
elena55 [62]
The reactant is what you begin with.
The product is what you end up with (so the answer is B)

3 0
3 years ago
Read 2 more answers
matter that is composed of two or more different elements chemically combined in a fixed proportion is classified as
Helga [31]

Answer: The answer for this is Compound.

Explanation: A matter is something which occupies space and has some mass.

Elements are defined as the smallest substances which cannot be broken down into another substance by any chemical means.

A compound is a defined as a substance composed of two or more different elements when they combine chemically in definite proportion. For example: CO_2 is named as carbon dioxide and is a compound made by combining carbon and oxygen in a fixed ratio of 1 : 2

So, the answer to the given question is compound.

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3 years ago
True or False: Jumpstart is a fast-paced method for identifying problems and solutions in a single session that can be used with
Tpy6a [65]

Answer:

<em><u>The answer is</u></em>: <u>False.</u>

<u />

Explanation:

Six Sigma is a methodology for continuous improvement that increases performance by controlling variability and focusing the process on customer specifications. It will be used within other methods such as Rummler: Brache, Scrum and TQM.

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<em><u>The answer is</u></em>: <u>False.</u>

3 0
3 years ago
A compound is made up of 28 g N, 24 g C, 48 g O, and 8 g H .What is the empirical formula?
vovikov84 [41]

Answer:

\rm C_2H_8N_2O_3.

Explanation:

<h3>Step One: calculate the coefficients. </h3>

Look up the relative atomic mass of these four elements on a modern periodic table:

  • \rm C: approximately 12.
  • \rm H: approximately 1.
  • \rm N: approximately 14.
  • \rm O: approximately 16.

The relative atomic mass of an element is numerically equal to the mass (in grams, \rm g,) of one mole of atoms of this element.

For example, the relative atomic mass of \rm C is approximately 12. Therefore, each mole of \rm C\! atoms would have a mass of 12\; \rm g.

This sample contains 24\; \rm g of carbon. That would correspond to approximately \displaystyle \left(\frac{24}{12}\right)\; \rm mol = 2\; \rm mol of \rm C atoms.

Similarly, for the other three elements:

\displaystyle n(\mathrm{H}) \approx \frac{8\; \rm g}{1\; \rm g \cdot mol^{-1}} = 8\; \rm mol.

\displaystyle n(\mathrm{N}) \approx \frac{28\; \rm g}{14\; \rm g \cdot mol^{-1}} = 2\; \rm mol.

\displaystyle n(\mathrm{O}) \approx \frac{48\; \rm g}{16\; \rm g \cdot mol^{-1}} = 3\; \rm mol.

Hence, the ratio between these elements in this compound would be:

n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3.

In the empirical formula of a compound, the coefficients should represent the smallest possible integer ratio between the number of atoms of these elements.

n(\mathrm{C}): n(\mathrm{H}): n(\mathrm{N}):n(\mathrm{O}) = 2: 8 : 2 : 3 is indeed the smallest possible integer ratio between the number of atoms of these elements.

<h3>Step Two: arrange the elements in an appropriate order</h3>

Apply the Hill System to arrange these four elements in the empirical formula. In the Hill System:

If carbon, \rm C, is present in this compound, then:

  • \rm C (carbon) and then \rm H (hydrogen) will be the first two elements listed in the formula (ignore the hydrogen if it is not in the compound.)
  • The other elements in this compound will be listed in alphabetical order.

If there is no carbon \rm C in this compound, then list all the elements in this compound in alphabetical order.

Both \rm C (carbon) and \rm H (hydrogen) are found in this compound. Therefore, the first element in the list would be \rm C\!. The second would be \rm H\!, followed by \rm N\! and then \rm O\!.

Hence, the empirical formula of this compound would be \rm C_2H_8N_2O_3.

6 0
3 years ago
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