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Lynna [10]
3 years ago
5

Lighting a match is an example of what kind of energy conversion?

Chemistry
2 answers:
sukhopar [10]3 years ago
7 0

Answer:

A is the answer.

Explanation:

Alika [10]3 years ago
4 0

Answer:

Mechanical Energy to Thermal Energy

When you strike a match, it moves through the air until it rubs against a surface. The rubbing produces the heat required to light the match. This is a transformation from mechanical energy to thermal (heat) energy.

Explanation:

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The Spirit of America Goodyear blimp has a volume of 2.027×105 ft3.When the blimp is in operation, it is filled with helium gas.
Andru [333]
Answer: 1.027 x 10^6 g= 1027kg
In this question, you are given the volume of the blimp (2.027×10^5 ft^3) and the density of the gas(0.179g/L). To answer this question, you need to convert the volume unit into liter. The calculation would be: 2.027×10^5 ft^3 x 28.3168L/ft3= 57.398 x 10^5L= 5.74x10^6L

Then to find the mass, multiply the volume with the density. The calculation would be: 5.74x10^6L x 0.179g/L= 1.027 x 10^6 g= 1027kg
4 0
3 years ago
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If an element has a half life of one million years, how long will it take to be completely gone
Aleonysh [2.5K]
It should be 2 million years
3 0
3 years ago
Which best describes a compound such as sodium chloride?
finlep [7]

Answer:

It s a pure substance.

Explanation:

Can only be separated into its different elements by chemical means because it is connected by a chemical bond.

4 0
3 years ago
What information is needed to calculate the percent composition of a compound
IrinaVladis [17]

Percent Composition by Mass. Percent composition is calculated from a molecular formula by dividing the mass of a single element in one mole of a compound by the mass of one mole of the entire compound. This value is presented as a percentage.

The best answer. :)

6 0
3 years ago
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How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?
lara [203]
<h3>Answer:</h3>

150000 J

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>m</em> = 225 g

[Given] <em>c</em> = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] <em>q</em>

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                          q = (225 g)(4.184 J/g °C)(159.8 °C)
  2. Multiply:                                                                                                           q = (941.4 J/°C)(159.8 °C)
  3. Multiply:                                                                                                           q = 150436 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

5 0
3 years ago
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