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Sonja [21]
2 years ago
11

Hoàn thành phương trình sau. Và ghi rõ phản ứng ion: NaHCO33 + NaOH->

Chemistry
1 answer:
Murrr4er [49]2 years ago
5 0

Answer:

hello

Explanation:

hello

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How many moles of calcium oxide are formed when 3 moles of calcium react with oxygen?
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Answer:

3 moles of CaO

Explanation:

The chemical balanced equation is;

2Ca + O₂ → 2CaO

The ratio of calcium(Ca) to Calcium Oxide(Cao) in this equation is 2:2.

Now, when 3 moles of calcium react with oxygen, Cao produced will be;

3 moles of O₂ × 2 moles of CaO/2 moles of Cao = 3 moles of CaO

7 0
3 years ago
What color do acids turn litmus paper?
Ivanshal [37]

Answer:

red

Explanation:

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8 0
2 years ago
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A student is trying to identify a clear liquid that he finds in a beaker in the classroom. He thinks the liquid might be either
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Simply mulitply the volume by the density. As we shall see, this is dimensionally consistent.

Explanation:

density

ρ

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g

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−

1

are reasonable.

For this problem:

17.4

⋅

m

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×

0.798

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g

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but A i supposed?

3 0
3 years ago
What are transferred in an oxidation-reduction reaction (1 point)?
madreJ [45]
electrons are transferred    in a oxidation-reduction  reaction

oxidation reduction  chemical equation involve  electrons  transfer   between  two species. In this reduction-oxidation type of chemical equation    oxidation  number of   molecule, atoms or ion  changes  by  gaining or losing  electrons,that is there  an oxidizing  agent and a  reducing agent  in the reaction.
7 0
3 years ago
A mixture containing nitrogen, hydrogen, and iodine established the following equilibrium at 400 °C:2NH3(g) + 3I2(g) ⇌ N2(g) + 6
miss Akunina [59]

Answer: The value of K_{c} for this reaction is 250000.

Explanation:

The given equation is as follows.

2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)

N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50   ... (1)

H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50  ... (2)

To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.

3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}  ... (3)

Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.

3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}

This equation can also be re-written as follows.

3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI

This equation is similar to the equilibrium equation given to us.

Therefore, during this subtraction the equation constants get divided as follows.

K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000

Thus, we can conclude that the value of K_{c} for this reaction is 250000.

6 0
2 years ago
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