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swat32
3 years ago
11

a copper rod is sliding on two conducting rails that make an angle of 18 with respect to each other, as in the drawing. The rod

is moving to the right with a constant speed of 0.70 m/s. A 0.31 T unifrom mangetic field is perpendicular to the plane of the paper. Determine the magnitude of the average emf induced in the triangle ABC during the 6.5s period after the rod was passed point A
Physics
1 answer:
gregori [183]3 years ago
6 0
14 because the horses name is friday and sprite cranberry is coming out with a new jersey
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The formation of volcanos and mountain ranges can be explained by the theroy of _____
Alenkasestr [34]

It can be explained by the theory of Plate Tectonics.

5 0
3 years ago
If you know any of them, please help!!!!!!
Anna [14]

I believe the answer for 1) is

PEgrav = mass • g • height

PEgrav = m *• g • h

5 0
3 years ago
A 40-cm-long tube has a 40-cm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. As th
Umnica [9.8K]

Answer:

The frequency of the tuning is 1.065 kHz

Explanation:

Given that,

Length of tube = 40 cm

We need to calculate the difference between each of the lengths

Using formula for length

\Delta L=L_{2}-L_{1}

\Delta L=74.7-58.6

\Delta L=16.1\ m

For an open-open tube,

We need to calculate the fundamental wavelength

Using formula of wavelength

\lambda=2\Delta L

Put the value into the formula

\lambda=2\times16.1

\lambda=32.2\ cm

We need to calculate the frequency of the tuning

Using formula of frequency

f=\dfrac{v}{\lambda}

Put the value into the formula

f=\dfrac{343}{32.2\times10^{-2}}

f=1065.2\ Hz

f=1.065\ kHz

Hence, The frequency of the tuning is 1.065 kHz

3 0
2 years ago
a microwave operates at a frequency of 2400 MHZ. the height of the oven cavity is 25 cm and the base measures 30 cm by 30 cm. as
alexira [117]

Complete question is;

A microwave oven operates at a frequency of 2400 MHz. The height of the oven cavity is 25 cm and the base measures 30 cm by 30 cm. Assume that microwave energy is generated uniformly on the upper surface of the cavity and propagates directly

downward toward the base. The base is lined with a material that completely absorbs microwave energy. The total microwave energy content of the cavity is 0.50 mJ.

Answer:

Power ≈ 600,000 W

Explanation:

We are given;

Frequency; f = 2400 Hz

height of the oven cavity; h = 25 cm = 0.25 m

base area; A = 30 cm by 30 cm = 0.3m × 0.3m = 0.09 m²

total microwave energy content of the cavity; E = 0.50 mJ = 0.5 × 10^(-3) J

We want to find the power output and we know that formula for power is;

P = workdone/time taken

Formula for time here is;

t = h/c

Where c is speed of light = 3 × 10^(8) m/s

Thus;

t = 0.25/(3 × 10^(8))

t = 8.333 × 10^(-10) s

Thus;

Power = (0.5 × 10^(-3))/(8.333 × 10^(-10))

Power ≈ 600,000 W

3 0
3 years ago
What is the distance between a 900 kg compact car and a 1600 kg pickup truck if the gravitational force between them is about 0.
elena-14-01-66 [18.8K]

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

r= \sqrt{\frac{Gm1m2}{F} }

r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required:

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

r= \sqrt{\frac{Gm1m2}{F} }

r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m

3 0
2 years ago
Read 2 more answers
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