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2 years ago

How many grams of H3PO4 are in 234 mL of a 2.5 M solution of H3PO4?

Chemistry

1 answer:

motikmotik2 years ago

5 0

Answer:

57 grams of H3PO4

Explanation:

M= moles/ liters

convert mL to L

234 mL x 1L/1000mL = 0.234L

Rearrange the Molarity formula to solve for moles.

moles= MxL

moles= 2.5M x 0.234L

moles= 0.585 mol

Use the molar mass of H3PO4 to get to grams

0.585 mol x 97.994 grams/1 mol = 57.326 grams of H3PO4

round to two sig figs for 57 grams

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in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead the empirical formula of the lead oxide is?

Romashka-Z-Leto [24]

Answer:

Pb3O4

Explanation:

According to this question, 3.425g of lead oxide was reduced to form 3.105g of lead in an experiment. Since lead oxide contains both lead (Pb) and oxygen (O) element,

Mass of lead oxide = 3.425g

Mass of lead = 3.105g

Mass of oxygen = (3.425g - 3.105g) = 0.320g

Next, we convert each mass value to mole by dividing by respective molar mass

Pb = 3.105g ÷ 207.2 = 0.0149mol

O = 0.320g ÷ 16 = 0.02mol

Next, we divide each mole value by the smallest (0.0149)

Pb = 0.0149mol ÷ 0.0149mol = 1

O = 0.02mol ÷ 0.0149mol = 1.342

Multiply each ratio value by 3 to get:

Pb = 1 × 3 = 3

O = 1.342 × 3 = 4.026

The whole number ratio, approximately, of Pb and O is 3:4, hence, their empirical formula is Pb3O4.

4 0

2 years ago

12.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?

Zielflug [23.3K]

Answer: 7.693 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=0.63atm\\V_1=12.70L\\P_2=105kPa=1.04atm(1kPa=0.009atm)\\V_2=?$

Putting values in above equation, we get:

$0.63\times 12.70mL=1.04\times V_2\\\\V_2=7.693L$

Thus new volume of the gas is 7.693 L

6 0

3 years ago

Read 2 more answers

Write a balanced equation for the reaction<br>between ammonia and sulfuric acid?

Slav-nsk [51]

Balanced equation for the reaction between ammonia and sulphuric acid is:

Explanation:

2NH3+H2SO4→(NH4)2SO4

I hope it'll help you...

8 0

2 years ago

Xenon forms several compounds with oxygen and fluorine. It is the most reactive non-radioactive noble gas because a. its large r

muminat

Answer:

d. its effective nuclear charge is lower than the other noble gases.

Explanation:

Xenon belongs to group O on the periodic table. Most of the elements here are unreactive.

Due to the large size of Xenon, the outermost electrons have very low effective nuclear charge. Effective nuclear charge is the effect of the positive charges of the nucleus on the electrons in orbits. This effect decreases outward as atomic shell increases.

Xenon has a very large atomic radius and there is weak a nuclear charge on the outermost electrons. The more electronegative elements would be able to attract some of its outermost electrons easily and form chemical bonds with xenon much more readily.

7 0

3 years ago

If you have 6 moles of reactant A and excess of B and C, how much product E would be formed

pychu [463]

B and C are in excess so amount of E will be determined by A.

Amount of product is determined by limiting reagents - Always.

Hence 6 moles of E will be formed.

Hope this helps!

3 0

3 years ago