Molar mass = 144.2 g/mol.
<h3>Calculate
Molar mass.</h3>
Formula to solve this: ΔT = Kf . m
ΔT → Freezing point of pure solvent - Freezing point of solution
0°C - (-1.94°C) = 1.86 °C/m . m
1.94°C / 1.86 m/°C = m → 1.04 m
1.04 are the moles of solute in 1kg of solvent → molality (mol/kg)
Let's convert the mass of our solvent in kg to determine the moles.
80 g . 1kg / 1000 g = 0.08 kg
Molality . kg of solvent → Solute moles
1.04 mol/kg . 0.080 kg = 0.0832 moles
These are the moles of 12 g of solute. To find the molar mass → g/mol
12 g / 0.0832 mol = 144.2 g/mol
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Hello!
We have the following data:
Area (
A) = 50 square feet
Mass (
m) = 8.5 ounces
Density (
d) = 2.70 g/cm³
Volume (
V) = ?
Thickness (
T) =? (in mm)
To move on, we must transform the area of 50 ft² in cm², let's see:
1 ft² ------- 929,0304 cm²
50 ft² -----
A

In the same way, we will convert the mass of 8.5 oz in grams, see:
1 oz -------- 28,3495 g
8,5 oz -------
m

Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:



The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)
In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:





We will convert to millimeters, going through a decimal place on the right

Hope this helps! :))
With the lowest atomic numbers <span>with the highest atomic numbers </span>
<span>that match their Latin names </span><span>with atomic symbols that match their modern names </span>
Answer:
15moles
Explanation:
Given parameters:
Mass of H₂SO₄ = 1469g
Unknown:
Number of moles = ?
Solution:
To solve this problem, let us first find the molar mass of the given compound;
molar mass = 2(1) + 32 + 4(16) = 98g/mol
So;
Number of moles =
=
Number of moles = 15moles
A material is a mixture if it is not pure