Need help with this physics problem!! 30 points if done!!!
2 answers:
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The acceleration of the car is 0.5 meters per seconds square.
Given the following data:
- Initial velocity, U = 30 m/s
- Distance, S = 900 meters
Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.
To find the acceleration of the car, we would use the third equation of motion;
Mathematically, the third equation of motion is given by the formula;
<em>Acceleration, a </em><em>=</em><em> 0.5 </em><em></em>
Therefore, the acceleration of the car is 0.5 meters per seconds square.
Read more: brainly.com/question/8898885
= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)
= -0.00225 m
New length = L + ΔL
= 1.25 m + (-0.00225 m)
= 1.248
D