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Rina8888 [55]
2 years ago
11

If the same amount of heat is suppliedto all samples of 10.0g each of aluminum iton and copper all at 15 degree celsius which sa

me would reach the heighest temp
Chemistry
1 answer:
s2008m [1.1K]2 years ago
5 0
When a substance absorbs thermal energy, it partitions some as potential and some as kinetic energy. Specific heat is an expression related to the quantity of heat a substance stores as potential energy; the remainder is absorbed as kinetic which causes the temperature to increase - recall that temperature is a measure of average kinetic energy. 
When specific heat is low, most of the energy is partitioned as kinetic energy and the substance will experience the greatest temperature change. 

So rather than calculating the change in temperature, we can simply inspect the specific heats. The one with the lowest will experience the greatest temperature change. We could also compare the specific heats: Al = .897/.385 ==> 2.3, Fe = .452/.385 = 1.2, Cu = .385/.385 = 1. We can expect Copper's temperature change to be 2.3 times larger than Aluminum's and 1.2 times larger than Iron's.
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Select the correct answer.
vichka [17]

Variations in the solar resource are probably the first and main consideration. You can use local weather stations where available, otherwise satellite data (eg from NASA's website) or commercial databases such as Meteonorm. Also there is quite a comprehensive set of data files in the SAM software

Other important considerations are

local environment: plants and animals that could be affected by the system; community support and buy-in.wind, hail, rain, snow profile for the location in question. if there are high/tropical winds then it will increase the plant cost.flight paths and roads near the plant which could be affected by glint and glareproximity to a local town where staff will be able to live both during construction and later during operationproximity to a electricity transmission line with available capacityavailability of water for mirror cleaning and steam blowdown.cost (and availability) of electricity in the area. If remote, electricity/energy may be very expensive, which will enable a high price for electricity sold from the plant.quality of road to the plant, required to bring equipment and materials to sitepolitical stability of the region -- potential impact on perceived bankability of the project.

Many of these items will have a large influence on the cost of the plant and/or the revenue it will generate during its life. Others relate to environmental and risk factors and are also critically important to consider.

Hope this helps!!

6 0
1 year ago
Which statement describes the bonds in iron sulfate, FeSO4?
Harlamova29_29 [7]

Answer: Would be D. Fe and S have an ionic bond, while S and O have covalent.

Hope that helps.

7 0
2 years ago
Read 2 more answers
ASAP will give brainliest!!!
Ahat [919]

Answer:

For me

Explanation:

It's Cu because other compound contains negative radicals

8 0
2 years ago
Read 2 more answers
Relative formula mass of glucose? (C6H12O6)
Rom4ik [11]

To find the mass of glucose, you must multiply the atomic weight of each of the elements in the molecule by the subscripts in the formula:

C_{6}=6*(12.01g)=72.06g

H_{12}=12*(1.008g)=12.096g

O_{6}=6*(15.999g)=95.994g

Then you add all of them together:

72.06g+12.096g+95.994g=180.15g

Therefore, the molar weight of glucose is 180.15 grams.

3 0
3 years ago
Molarity to percent by mass. Convert 1.672 mol/L MgCl2(aq) solution to percent by mass of MgCl2 in the solution. The solution de
nignag [31]

Answer:

\%m/m=14\%

Explanation:

Hello!

In this case, since the molarity of magnesium chloride (molar mass = 95.211 g/mol) is 1.672 mol/L and we know the density of the solution, we can first compute the concentration in g/L as shown below:

[MgCl_2]=1.672\frac{molMgCl_2}{L}*\frac{95.211gMgCl_2}{1molMgCl_2}=159.2\frac{gMgCl_2}{L}

Next, since the density of the solution is 1.137 g/mL, we can compute the concentration in g/g as shown below:

[MgCl_2]=159.2\frac{gMgCl_2}{L}*\frac{1L}{1000mL}*\frac{1mL}{1.137g}=0.14

Which is also the by-mass fraction and in percent it turns out:

\%m/m=0.14*100\%\\\\\%m/m=14\%

Best regards!

6 0
2 years ago
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