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Licemer1 [7]
3 years ago
13

What is the charge of the cadmium cation

Chemistry
2 answers:
Vikki [24]3 years ago
5 0
The charge of the cadmium cation is +2
Ivan3 years ago
3 0

Answer:

In its compounds cadmium exhibits almost exclusively the +2 oxidation state, as in the colourless Cd2+ ion, which forms a number of stable complex ions, especially halide complexes.

Explanation:

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Will reward brainliest<br> Explain why all arrhenius acids can be considered bronsted lowry acids
GuDViN [60]

Answer:

Explanation:

A bronsted lowry acid just means that it donates a proton.

An arrhenius acid dissolves in water to donate a proton

the only difference is that an arrhenius acid must dissolve in water but it still donates a proton so it is considered a bronsted lowry acid

3 0
3 years ago
What is the colour change when universal indicator is added to apple juice​
kherson [118]

Answer:

red because its the flavor

Explanation:

5 0
3 years ago
Read 2 more answers
what are two or more substances that are together in the same place, but are not chemically combined in a set ratio. They can be
GuDViN [60]
Yahoo has the answer to that question. because i looked it up on yahoo..
6 0
3 years ago
A nail contains 0.10 moles of iron. How many grams of iron are in the nail?
oksano4ka [1.4K]

Answer:

10.8

Explanation:

That's my guess, I hope you figure everything out though.

4 0
3 years ago
When performing a gram stain, it is necessary to remove crystal violet stain from any gram negative bacteria on the slide. Micro
Snezhnost [94]

Answer:

10.11 mL

Explanation:

Given that :

Total volume of decolorizer = 500 mL

A common recipe is equal parts 95% ethanol and acetone.

So;

The volume of 95% ethanol in the decolorizer = 500mL/2 = 250 mL

Let represent V(ml) for the 99% of ethanol needed to make 95% of the 250 mL of ethanol;

Therefore:

V(ml) × 0.99 = 250 × 0.95

V(ml) × 0.99 = 237.5

V(ml)  = 237.5/0.99

V(ml) = 239.89 mL

Hence; the amount of water to be added to 95% of ethanol = ( 250 -  239.89 )mL = 10.11 mL

5 0
3 years ago
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