Question

If Ms. Ramirez drops a watermelon from the top of the second-floor fire escape outside her room, and it takes 1.5 seconds to hit the ground, calculate the velocity of the watermelon as it hits the ground.

Answer 1

The velocity of the watermelon as it hits the ground is 14.715 m/s.

Given the data in the question;

Since the Watermelon was dropped from rest,

• Initial velocity of the Watermelon;$u = 0m/s$

• Time taken for the Watermelon to hit the ground; $t = 1.5s$

• We know that, Acceleration due to gravity; $g = 9.81 m/s^2$

Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.

From the First Equation of Motion:

$v = u + at$

Now, under gravity, acceleration ''a" will Acceleration due to gravity;$g = 9.81m/s^2$, "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.

So, we substitute our values into the equation

$v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s$

Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s

Learn more; brainly.com/question/13275688