70,368,744,177,664
i hope that helps!
The element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe with electron configuration:1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.
According to the question, we are required to identify the element with the lowest atomic number whose electronic configuration has four completely filled p sub-shells.
Evidently, the shell with energy level one has no p orbital.
- Therefore, the existence of p orbitals in electron configuration begins with shell energy level, n=2.
- However, we must know that the p-orbital comprises of 3 sub-orbitals namely;
p(x) , p(y) and p(z) with two electrons of opposing spin in each sub orbital.
- Therefore, the total number of electrons in the p orbital is 6 electrons.
In essence, the element in question should have electron configuration;
- 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.
The electron configuration above contains 54 electrons and has atomic number, 54.
In essence, the element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe.
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The volume of the steel that is described above is obtained by water displacement method. This means that the volume can be calculated by subtracting the initial volume from the final volume. This will give us an answer of,
volume of steel = 55.5 mL - 45 mL = 10.5 mL
A hydrologist should analyze the water for contamination
