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3 years ago

1Write 2 paragraphs on the importance and impact of good nutrition on your health.2what are 8 healthy eating goals.

Physics

1 answer:

poizon [28]3 years ago

6 0

Answer:

nutritions are compounds in food essential to life and health

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Apakah yang dimaksud dengan gaya

tangare [24]

Nah gaya seperti titik fashion seperti apa yang Anda mana dan hal-hal seperti itu. (tell me if you cant understand)

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3 years ago

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A force of 150N at an angle of 60 degree to the horizontal to pull a box through a distance of 50m calculate the work done

Alexxandr [17]

Force=150N
Angle=60°
Displacement=50m

$\boxed{\sf W=Fscos\Theta}$

$\\ \sf\longmapsto W=150(50)cos 60$

$\\ \sf\longmapsto W=7500\times \dfrac{1}{2}$

$\\ \sf\longmapsto W=3750J$

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3 years ago

Coherent green light shines on a double slit with spacing 241um. This results in a diffraction pattern consisting of a central m

lilavasa [31]

Answer:

Becomes greater

Explanation:

Distance between the central maxima and the next line increase with the wavelength i.e.

$d =\frac{3 \lambda L}{2a}$

As, the wavelength of the red light is greater than the wavelength of the green light, thus, the distance between the central maxima and the next line becomes greater.

Option 5 is correct.

4 0

4 years ago

_______ are pictures of relationships.

S_A_V [24]

Answer:

Graphs

Explanation:

5 0

3 years ago

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An electron that has a velocity with x component 2.6 × 106 m/s and y component 3.2 × 106 m/s moves through a uniform magnetic fi

elena55 [62]

Answer:

a) $\vec F_{B} = 8.766\times 10^{-14}\,T\,k$ , b) $\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

Explanation:

a) The magnetic force experimented by a particle has the following vectorial form:

$\vec F_{B} = q\cdot \vec v \times \vec B$

The charge of the electron is equal to $-1.602\times 10^{-19}\,C$ . Then, cross product can be solved by using determinants:

$\vec F_{B} = \begin{vmatrix}i&j&k\\-4.165\times 10^{-13}\, C\cdot \frac{m}{s} &-5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = 8.766\times 10^{-14}\,T\,k$

b) The charge of the proton is equal to $1.602\times 10^{-19}\,C$ . Then, cross product has the following determinant:

$\vec F_{B} = \begin{vmatrix}i&j&k\\4.165\times 10^{-13}\, C\cdot \frac{m}{s} &5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

8 0

3 years ago