Answer:
6.04788 in
78.38779 m/s
0.88159 kg
34.55294 J
Explanation:
Circumference is given by
Diameter is given by
The diameter is 6.04788 in
Volume of sphere is given by
The volume is
Fall velocity is given by
The velocity of the fall will be 78.38779 m/s
Mass is given by
The mass is 0.88159 kg
Kinetic energy is given by
The kinetic energy is 34.55294 J
Answer:
Answer:
a. 1.594 m/s = v
b. 1.274 m/s = v
Explanation:
A) First calculate the potential energy stored in the spring when it is compressed by 0.180 m...
U = 1/2 kx²
Where U is potential energy (in joules), k is the spring constant (in newtons per meter) and x is the compression (in meters)
U = 1/2(13.0 N/m)(0.180 m)² = 0.2106 J
So when the spring passes through the rest position, all of its potential energy will have been converted into kinetic energy. K = 1/2 mv².
0.2106 J = 1/2(0.170 kg kg)v²
0.2106 J = (0.0850 kg)v²
2.808m²/s² = v²
1.594 m/s = v
(B) When the spring is 0.250 m from its starting point, it is 0.250 m - 0.180 m = 0.070 m past the equilibrium point. The spring has begun to remove kinetic energy from the glider and convert it back into potential. The potential energy stored in the spring is:
U = 1/2 kx² = 1/2(13.0 N/m)(0.070 m)² = 0.031J
Which means the glider now has only 0.2106 J - 0.031J = 0.1796 J of kinetic energy remaining.
K = 1/2 mv²
0.1796 J = 1/2(0.170 kg)v²
0.138 J = (0.0850 kg)v²
1.623 m²/s² = v²
1.274 m/s = v
Answer:
the angular speed in radian per second about the center of a circle is 0.278 rad/s
Explanation:
Given;
Linear velocity v = 25m/s
Radius of circular path r = 90m
The linear velocity of the particle can be expressed as a function of the angular speed as;
Linear velocity = angular speed × radius of path
v = wr
w = v/r
Where;
v = linear velocity
r = radius
w = angular speed
Substituting the given values, we have;
w = 25/90 = 0.278 rad/s
the angular speed in radian per second about the center of a circle is 0.278 rad/s
Answer:
option B
Explanation:
given,
Satellite B has an orbital radius nine times that of satellite A.
R' = 9 R
now, orbital velocity of the satellite A
........(1)
now, orbital velocity of satellite B
from equation 1
hence, the correct answer is option B
