The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.
The given parameters:
- <em>Density of the octane, ρ = 0.703 g/ml</em>
- <em>Volume of octane, v = 3.79 liters</em>
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The mass of the octane burnt is calculated as follows;

The combustion reaction of octane is given as;

From the reaction above:
228.46 g of octane -------------------> 704 g of CO₂ gas
2,664.37 of octane --------------------> ? of CO₂ gas

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.
Learn more about combustion of organic compounds here: brainly.com/question/13272422
It’s soft which makes It low energy
Answer: 3378.4mL
Explanation:
density of Gasoline = 0.74g/mL.
Volume of gasoline in milliliter = ?
mass of gasoline = 2.5kg
(Since density is in grams per millilitre, convert mass in kilograms to grams)
If 1kg = 1000grams
2.5kg = 2.5 x 1000 = 2500grams
Recall that density is obtained by dividing the mass of a substance by its volume
i.e Density = Mass / Volume
0.74g/mL = 2500grams/Volume
Volume = (2500 grams / 0.74g/mL)
Volume = 3378.4mL
Thus, the volume of gasoline is 3378.4mL
Answer:
It's a heterogeneous mixture.
Explanation:
Diamond is made of just one element: carbon. Each carbon atom in diamond is connected to four other carbon atoms, in a crystal that extends on and on. There are other forms of pure carbon where the atoms are bonded differently, notably charcoal and graphite.
Since we know that one mole of any gas at STP is equal to 22.4 L we can multiply 135L by the following conversion: 1 mole/22.4L. When you set up the problem it looks like this…: (135L)x 1 mole/22.4L =6.03 moles of oxygen gas The liters cancel out and you are left with moles as your units.
So your answer is then 3.058