<h3><u>Question</u><u>:</u></h3>
A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?
<h3><u>Statement:</u></h3>
A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.
<h3><u>Solution</u><u>:</u></h3>
- Initial velocity (u) = 70 m/s
- Acceleration (a) = -14 m/s^2
- Time (t) = 3 s
- Let the velocity of the car after 3 s be v m/s
- By using the formula,
v = u + at, we have
- So, the velocity of the car after 3 s is 28 m/s.
<h3><u>Answer:</u></h3>
The car's speed after 3 s is 28 m/s.
Hope it helps
the answer for this question is c
Answer:
The child represented by a star on the outside path.
Explanation:
Answer:
0.256 J.
Explanation:
The formula for the energy stored in a capacitor is given as
E = 1/2CV².................... Equation 1
Where E = Energy stored in the capacitor, C = Capacitance of the capacitor, V = Voltage.
Make C the subject of the equation
C = 2E/V².................. Equation 2
Given: E = 64 mJ = 0.064 J, V = 1.5 V.
Substitute into equation 2
C = 2(0.064)/(1.5²)
C = 0.128/2.25
C = 0.0569 F.
If the capacitor where fully charged by 3.00 V.
E = 1/2CV²
Given: C = 0.0569 F, V = 3.0 V
Substitute into the equation above,
E = 1/2(0.0569)(3²)
E = 0.256 J.
Answer:
346.01 × 10² Lux
Explanation:
Given:
luminance of the sun at zenith at sea level, Ls = 1600 × 10 cd/m²
The diameter of the sun's photosphere = 8.64 × 10 miles = 45.62 × 10⁸ ft
or
Radius, r =
or
r = 22.81 × 10⁸ ft
The distance from the sun to the earth = 92.9 × 10 miles = 49.05 x 10¹⁰ ft
Now,
Lumen = Luminance × 4πr²
or
Lumen = 1600 × 10 cd/m² × 4πr² .....................(1)
also,
Illumination =
on substituting lumen from 1
Illumination =
or
Illumination =
or
Illumination = 346.01 × 10² Lux