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IceJOKER [234]
3 years ago
6

Cheetahs the worlds fastest land animals can run up to about 125km/h. a cheetah chasing an impala runs 32m [N], then suddenly tu

rns and runs 46m [W] before lunging at the impala. the entire motion takes only 2.7seconds. 
a) determine the ceetahs average speed for this motion.
b) determine the cheetahs average velocity
Physics
1 answer:
AleksAgata [21]3 years ago
3 0
Av Speed = total distance / time time = 32+ 46 / 2.7 = 28 m/sec
Av velocity = total displacement / time total = S / t
S = sqrt( 32^2 +46^2) = 56 m
Av Velocity = 56/ 2,7 = 20.75 m/sec
with angle tan^-1 = 0.7 north west ( about 35 degrees north west)
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Korolek [52]
Both ve similar equations 
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7 0
3 years ago
If the motor M rotates in the direction shown by the arrow as illustrated in the diagram below, what is going on? A. 1 and 2 are
madreJ [45]

Answer:

C. 1 and 2 are going up

Explanation:

The motor turns counterclockwise, so the pulley above it will also turn counterclockwise.  This means the pulley to the right will turn counterclockwise.  So block 2 will move up.

Since the belt is twisted on the left side, the pulley on the left will spin in the opposite direction (clockwise).  So block 1 will also move up.

7 0
3 years ago
Un vehiculo se desplaza con movimiento rectilio uniforme. Sabiendo que recorre 90 km en 3 horas. Averiguo la velocidad en m/s.
SashulF [63]

Answer:

Velocidad = 500 m/s

Explanation:

Dados los siguientes datos;

Distancia = 90 km

Tiempo = 3 horas

Conversión;

Por distancia:

1 kilómetro = 1000 metros

90 kilómetros = 90 * 1000 = 90,000 metros

Para el tiempo:

1 hora = 60 segundos

3 horas = 60 * 3 = 180 segundos

Para encontrar la velocidad en m/s;

Matemáticamente, la velocidad viene dada por la ecuación;

Velocidad = \frac {distancia} {tiempo}

Sustituyendo en la fórmula, tenemos;

Velocidad = 90000/180

Velocidad = 500 m/s

5 0
3 years ago
A 2.0 kg book is lying on a 0.78 m -high table. You pick it up and place it on a bookshelf 2.1 m above the floor.Part ADuring th
zloy xaker [14]

Given data:

* The mass of the book is 2 kg.

* The initial height of the book is 0.78 m.

* The final height of the book is 2.1 m.

Solution:

(A). The work done by the gravity on the book is,

W=mg(h_f-h_i)

where m is the mass, g is the acceleration due to gravity, h_i is the initial height and h_f is the final height,

The work is done in moving the object in upward direction where as the gravitational force is acting in the down ward direction. Thus, the value g (acceleration due to gravity) is taken as negative in this case.

Substituting the known values,

\begin{gathered} W=2\times(-9.8)\times(2.1-0.78) \\ W=-19.6\times1.32 \\ W=-25.9\text{ J} \end{gathered}

Thus, the work done by the gravitational force is -25.9 J.

(B). The work done by the hand on the moving the book is,

\begin{gathered} W_1=-W \\ =25.9\text{ J} \end{gathered}

Thus, the work done by the hand on the book is 25.9 J.

7 0
1 year ago
ANSWER FAST PLEASE!
labwork [276]

Answer:

When friction hits the floor, the oil bounces back up but then down. Then the oil spreads apart. Like an earthquake. Not really though. And try not to spill oil for the first place.

Hope I helped! Brainiest plz! Hope you make an 100% and have a wonderful day! -Amelia♥

4 0
3 years ago
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