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IceJOKER [234]
3 years ago
6

Cheetahs the worlds fastest land animals can run up to about 125km/h. a cheetah chasing an impala runs 32m [N], then suddenly tu

rns and runs 46m [W] before lunging at the impala. the entire motion takes only 2.7seconds. 
a) determine the ceetahs average speed for this motion.
b) determine the cheetahs average velocity
Physics
1 answer:
AleksAgata [21]3 years ago
3 0
Av Speed = total distance / time time = 32+ 46 / 2.7 = 28 m/sec
Av velocity = total displacement / time total = S / t
S = sqrt( 32^2 +46^2) = 56 m
Av Velocity = 56/ 2,7 = 20.75 m/sec
with angle tan^-1 = 0.7 north west ( about 35 degrees north west)
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When we have two sound waves with frequencies f1 and f2 that interfere, the beat frequency is equal to the absolute value of the difference of the two frequencies, so in our problem:
f_{beat}=f_2-f_1 = 600 Hz-594 Hz = 6Hz
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What could people do to DECREASE erosion of the Earth’s surface?

  Well, People can plant crops or they can grow plants and if your looking at the options only B and C has that, but lets make sure. So A) "Cut down more trees" does not help DECREASE erosion, if you want to decrease erosion then you have to have roots to make earth's surface stay. A is eliminated, going to B, B says "Use more land to plant crops." that's better because crops have roots so it can keep the surface/land sucked in and will not get erode away. Anyways moving on to C, C "Allow natural vegetation to grow." that kinda helps decrease erosion; so imma keep that in mind, and finally D "Allow cattle to graze more often." does not help at all. So D and A is eliminated, So theres only C and B left, C will kinda help but B will help more; So it will leave us to the final answer which is....

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I hope this helps you and I hope you understand what i'm talking about...


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Steam is to be condensed on the shell side of a heat exchanger at 150 oF. Cooling water enters the tubes at 60 oF at a rate of 4
zalisa [80]

Answer:

a. 572Btu/s

b.0.1483Btu/s.R

Explanation:

a.Assume a steady state operation, KE and PE are both neglected and fluids properties are constant.

From table A-3E, the specific heat of water is c_p=1.0\ Btu/lbm.F, and the steam properties as, A-4E:

h_{fg}=1007.8Btu/lbm, s_{fg}=1.6529Btu/lbm.R

Using the energy balance for the system:

\dot E_{in}-\dot E_{out}=\bigtriangleup \dot E_{sys}=0\\\\\dot E_{in}=\dot E_{out}\\\\\dot Q_{in}+\dot m_{cw}h_1=\dot m_{cw}h_2\\\\\dot Q_{in}=\dot m_{cw}c_p(T_{out}-T_{in})\\\\\dot Q_{in}=44\times 1.0\times (73-60)=572\ Btu/s

Hence, the rate of heat transfer in the heat exchanger is 572Btu/s

b. Heat gained by the water is equal to the heat lost by the condensing steam.

-The rate of steam condensation is expressed as:

\dot m_{steam}=\frac{\dot Q}{h_{fg}}\\\\\dot m_{steam}=\frac{572}{1007.8}=0.5676lbm/s

Entropy generation in the heat exchanger could be defined using the entropy balance on the system:

\dot S_{in}-\dot S_{out}+\dot S_{gen}=\bigtriangleup \dot S_{sys}\\\\\dot m_1s_1+\dot m_3s_3-\dot m_2s_2-\dot m_4s_4+\dot S_{gen}=0\\\\\dot m_ws_1+\dot m_ss_3-\dot m_ws_2-\dot m_ss_4+\dot S_{gen}=0\\\\\dot S_{gen}=\dot m_w(s_2-s_1)+\dot m_s(s_4-s_3)\\\\\dot S_{gen}=\dot m c_p \ In(\frac{T_2}{T_1})-\dot m_ss_{fg}\\\\\\\dot S_{gen}=4.4\times 1.0\times \ In( {73+460)/(60+460)}-0.5676\times 1.6529\\\\=0.1483\ Btu/s.R

Hence,the rate of entropy generation in the heat exchanger. is 0.1483Btu/s.R

4 0
3 years ago
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