To solve the problem, it is necessary to apply the concepts related to the change of mass flow for both entry and exit.
The general formula is defined by
Where,
mass flow rate
Density
V = Velocity
Our values are divided by inlet(1) and outlet(2) by
PART A) Applying the flow equation we have to
PART B) For the exit area we need to arrange the equation in function of Area, that is
Therefore the Area at the end is
Answer:
88 m/s
Explanation:
To solve the problem, we can use the following SUVAT equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
d is the distance covered
For the car in this problem, we have
d = 484 m is the stopping distance
v = 0 is the final velocity
is the acceleration
Solving for u, we find the initial velocity:
Answer:
An element is a pure substance and is made of only one type of atom.
Explanation:
It cannot be broken down into a simpler substance.