Answer: 1.13 X 10^3 g or 1130 g
Explanation: When you add up everything, you will get 1134.1288 g = 1.11341218 X 10^3. But while adding significant figures, we always look for the least significant figures (here 4.65 has least sig. figures i.e. 3) and take that as a reference to how many significant figures we should have in the answer. (Pretty hard to explain!) Hope you got it!!
Answer: .4 m/s^2= acceleration
Explanation:
f = m*a
We can rearrange this equation to solve for acceleration. Therefore,
a=f/m
a= 28N/70kg
a= 0.4 m/s^2
Answer:
Explanation:
The energy of Mass-Spring System the sum of the potential energy of the block plus the kinetic energy of the block:

Where:

There are two cases, the first case is when the spring is compressed to its maximum value, in this case the value of the kinetic energy is zero, since there is no speed, so:

The second case is when the block passes through its equilibrium position, in this case the elastic potential energy is zero since
, so:

Now, let's find the energy of the system when the block is replaced by one whose mass is twice the mass of the original block using the previous data:

Where in this case:

Therefore:

Answer:
Geothermal!!
Explanation:
Geo means earth! Just like Hydro means water, and Pyro means fire :)
Answer:
Distance = 16.9 m
Explanation:
We are given;
Power; P = 70 W
Intensity; I = 0.0195 W/m²
Now, for a spherical sound wave, the intensity in the radial direction is expressed as a function of distance r from the center of the sphere and is given by the expression;
I = Power/Unit area = P/(4πr²)
where;
P is the sound power
r is the distance.
Thus;
Making r the subject, we have;
r² = P/4πI
r = √(P/4πI)
r = √(70/(4π*0.0195))
r = √285.6627
r = 16.9 m