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3 years ago

What is the net force on charge placed at the center of square of length 1m? All charges have same magnitude of 2 micro coulomb.

Physics

1 answer:

Masja [62]3 years ago

5 0

Answer:

Electric Field intensity is zero.

The reason for that is:

All charges are placed at equal distances from the center of the square and have same magnitude and sign. This means they will exert equal and opposite forces on the test charge at the center. Net force will become Zero.

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NikAS [45]

Ω = 2.81
A = 0.232
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Ф = 0

at t = 1.42, with Ф = 0:
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2 years ago

Three equal point charges, each with charge 1.15 μCμC , are placed at the vertices of an equilateral triangle whose sides are of

julsineya [31]

Answer:

$U=50.96J$

Explanation:

The electrostatic potential energy for pair of charge is given by

U=1/4π∈₀×(q₁q₂/r)

Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:

U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)

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Substitute given values

$U=3\frac{1}{4\pi E_{o} }\frac{q^{2} }{r}\\ U=3\frac{1}{4\pi8.85*10^{-12} }\frac{(1.15*10^{-6}C )^{2} }{0.0007m}\\ U=50.96J$

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What is the magnitude of the electric field on a +2 C charge if it experiences an electric force of 6 N?

MrMuchimi

Answer:

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