Answer:
Explanation:
Specific heat capacity can be defined as the heat required to raise the temperature of a unit mass of a substance by 1kelvin.
The heat capacity on the other hand, expresses the heat required to raise the temperature of asubstance by 1kelvin.
When we use specific heat capacity, we are particular about the amount of heat that would be needed to actually cause a temperature change in a unit of a substance. This suggests that even if we don't have a complete substance, we can be sure that by knowing the mass of a unit of a body one can easily estimate how much heat is required to raise its temperature. The specific heat is fundamental in calculating the heat capacity of a body. Without the value of the specific heat, we cannot evalutate the heat capacity of a body.
Oxygen, Nitrogen and Fluorine
Explanation:
In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of the oxygen, nitrogen and fluorine.
- Hydrogen bonding is a type of dipole - dipole attraction between two specie.
- It is an intermolecular force of attraction.
- This bond type forms when hydrogen is bonded to a more electronegative atom.
- These atoms are oxygen, nitrogen and fluorine
- These species draws the electron shared more to themselves and leaves a partial positive charge on the hydrogen and a negative charge on them.
- The electrostatic force of attraction between the hydrogen of one molecule and the O/N/F of another molecule cause the formation of hydrogen bonds.
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Hydrogen bonding brainly.com/question/10602513
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Ksp of PbBr₂ is 6.60 × 10⁻⁶. The molar solubility of PbBr₂ in pure water is 0.0118M.
Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.
Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.
Let the molar solubility be S upon dissociation.
PbBr₂ or Lead Bromide dissociates in pure water as follows:
PbBr₂ ----------> Pb⁺² + Br⁻
S 2S
Ksp = [Pb⁺²] [ Br⁻]
Ksp = (S) (2S)²
Ksp = 4S³
6.60 × 10⁻⁶ = 4S³
S = 0.0118M
Hence, the Molar solubility S is 0.0118M.
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