1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brilliant_brown [7]
3 years ago
5

Can the sum of the magnitudes of two vectors ever be equal to the magnitude of the sum of the same two vectors? If no, why not?

If yes, when?
a-No, because of the angle between the two vectors.
b-No, it is impossible for the magnitude of the sum to be equal to the sum of the magnitudes.
c-Yes, if the two vectors are in the same direction.
d-Yes, if the two vectors are perpendicular.
e. Yes, if one of the vectors is zero.
Physics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

c-Yes, if the two vectors are in the same direction.

e. Yes, if one of the vectors is zero.

Explanation:

Lets take

The magnitude of the two vectors are A and B and they are at angle θ

Then the Sum of these two vectors

\bar{R}=\bar{A}+\bar{B}

Resultant R

R=\sqrt{A^2+B^2+2ABcos\theta}

if the angle between these vectors is zero.It means that they are in the same direction.

θ = 0

R=\sqrt{A^2+B^2+2ABcos0}

R=\sqrt{A^2+B^2+2AB}

R=\sqrt{(A+B)^2}

R=A+B

If the one vector is zero vector.

Therefore the answer will be C and e.

You might be interested in
Brlan is repairing an old alarm clock. He needs to replace a device that converts the electric energy into sound energy. Which o
Brums [2.3K]
The answer is buzzer
3 0
2 years ago
X-rays have so much energy they can go right through your ___ and ___.
Stolb23 [73]

Answer:

X-rays have so much energy they can go right through your <u>muscles</u> and <u>fat</u>.

Explanation:

There are actually more ways to fill in those two blanks... Different parts of the body absorb x-rays in varying degrees, but soft tissues (like skin, muscles, fat, and organs) allow most of the X-rays to pass through.

8 0
3 years ago
If forces acting on an object are unbalanced, which factor may result from an unbalanced force? The net force is negative. There
Oksi-84 [34.3K]

Answer:the Forces cancel out each other

Explanation:the forces cancel out each other

6 0
3 years ago
Read 2 more answers
Mary wishes to lose 5 pounds before her vacation in approximately 5 weeks. Her average consumption is 2,100 kilocalories per day
nordsb [41]

Answer:

1,600 to 1,700 kilocalories per day

Explanation:

7 0
3 years ago
An experiment is performed to test the effect of three different types of water on the growth of a plant. The test is done by us
natima [27]
I think the correct answer would be D. The tap water in the experiment is one the three test conditions of the independent variable, the type of water. The independent variable in a experiment is the one being manipulated or the one being changed. In this case, it is the type of water.
6 0
3 years ago
Read 2 more answers
Other questions:
  • If the distance between two objects is decreased to 1/10 of the original
    10·2 answers
  • following statement supports which theory? "Astronomers have observed protoplanetary disks around distant newborn stars." Big Ba
    8·2 answers
  • Density of a material is the same, no matter the _____ or the ___ of the material
    15·1 answer
  • A simple pendulum 0.64m long has a period of 1.2seconds. Calculate the period of a similar pendulum 0.36m long in the same locat
    8·1 answer
  • Which one of the following frequencies of a wave in the air can be heard as an audible sound by the
    13·2 answers
  • Is kicking a ball a conservation of momentum ?
    14·1 answer
  • The velocity time graph of a body is given below. Find the distance travelled by the body from A to B. *
    9·1 answer
  • The force that causes an object to follow a
    11·1 answer
  • What does red shift tell about the movement of a galaxy?​
    7·1 answer
  • An object weighs 200N, what is its mass?​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!