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Assoli18 [71]
3 years ago
8

It is given thatopen parenthesis, x minus 2y, close parenthesis, times open parenthesis, x + 2y, close parenthesis, = 4Quantity

A: x squared, minus, 4 times the quantity y squared Quantity B: 8 A. Quantity A is greater. B. Quantity B is greater. C. The two quantities are equal. D. The relationship cannot be determined from the information given.
Engineering
1 answer:
aksik [14]3 years ago
3 0

Answer:

  Quantity B is greater.

Explanation:

<u>Given</u>:

  (x -2y)(x +2y) = 4

  A = x² -4y²

  B = 8

<u>Find</u>:

  the relationship between A and B

<u>Solution</u>:

The given expression can be expanded to give ...

  x(x +2y) -2y(x +2y) = x² +2xy -2xy -4y² = x² -4y²

This is precisely the expression designated as A. Its value is 4.

  4 < 8

  A < B

Quantity B is greater.

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Answer & Explanation:

function Temprature

NYC=[33 33 18 29 40 55 19 22 32 37 58 54 51 52 45 41 45 39 36 45 33 18 19 19 28 34 44 21 23 30 39];

DEN=[39 48 61 39 14 37 43 38 46 39 55 46 46 39 54 45 52 52 62 45 62 40 25 57 60 57 20 32 50 48 28];

%AVERAGE CALCULATION AND ROUND TO NEAREST INT

avgNYC=round(mean(NYC));

avgDEN=round(mean(DEN));

fprintf('\nThe average temperature for the month of January in New York city is %g (F)',avgNYC);

fprintf('\nThe average temperature for the month of January in Denvar is %g (F)',avgDEN);

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count=1;

NNYC=0;

NDEN=0;

while count<=length(NYC)

   if NYC(count)>avgNYC

       NNYC=NNYC+1;

   end

   if DEN(count)>avgDEN

        NDEN=NDEN+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in New York city was above the average',NNYC);

fprintf('\nDuring %g days, the temprature in Denvar was above the average',NDEN);

%part C

count=1;

highDen=0;

while count<=length(NYC)

   if NYC(count)>DEN(count)

       highDen=highDen+1;

   end

   count=count+1;

end

fprintf('\nDuring %g days, the temprature in Denver was higher than the temprature in New York city.\n',highDen);

end

%output

check the attachment for additional Information

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