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ch4aika [34]
3 years ago
5

Consider the following balanced redox reaction (do not include state of matter in your answers):2CrO2−(aq) + 2H2O(l) + 6ClO−(aq)

→2CrO42−(aq) + 3Cl2(g) + 4OH−(aq)(a) Which species is being oxidized? (b) Which species is being reduced? (c) Which species is the oxidizing agent? (d) Which species is the reducing agent? (e) From which species to which does electron transfer occur?
Chemistry
2 answers:
Valentin [98]3 years ago
6 0

Answer:

E i think

Explanation:

zhenek [66]3 years ago
5 0

Answer:

Explanation:

Hello,

At first, it is necessary to establish the oxidation states for all the species involved in the reaction:

2(Cr^{+3}O_2^{-2})^{-}(aq) + 2H_2^{+1}O^{-2}(l) + 6(Cl^{+1}O^{-2})^{-1}(aq) -->2(Cr^{+6}O_4^{-2})^{-2}(aq) + 3Cl_2^0(g) + 4(O^{-2}H^{+1})^-(aq)

In such a way, we answer to the questions as follows:

(a) Oxidized species is the one that has an increase in its oxidation state, this is chromium which passes from +3 to +6.

(b) Reduced species is the one that has a decrease in its oxidation state, this is chlorine which passes from +1 to 0.

(c) Oxidizing agent is the same reduced species, this is chlorine as it removes electrons.

(d) Reducing agent is the same oxidized species, this is chromium as it gains electrons.

(e) Electron transfer occur from chlorine to chromium as chlorine removes electrons and chromium gains them.

Best regards.

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Part i. you considered the equilibrium: fe3+(aq) + scn-(aq) fe(scn)2+(aq), and compared the color of the solutions in four test
Alexus [3.1K]

Answer:

The equilibrium will be shifted to lift with the formation of a brown gelatinous precipitate of Fe(OH)₃.

Explanation:

  • Le Chatelier's principle states that <em>"when any system at equilibrium for is subjected to change in concentration, temperature, volume, or pressure, then the system readjusts itself to counteract the effect of the applied change and a new equilibrium is established that is different from the old equilibrium"</em>.
  • The addition of NaOH will result in the formation of Fe(OH)₃ precipitate which has a brown gelatinous precipitate.
  • The formation of this precipitate cause removal and decrease of Fe³⁺ ions.
  • According to Le Chatelier's principle, the system will be shifted to lift to increase Fe³⁺ concentration and reduce the stress of Fe³⁺ removal and readjust the equilibrium again. So, the [Fe(SCN)²⁺] decreases.
  • Increasing [Fe³⁺] will produce a yellow color solution that contains a brown gelatinous precipitate of Fe(OH)₃.
3 0
3 years ago
When will Le Chatelier's principle come into effect?
True [87]
If u disturbed equilibrium position then this principal comes into effect deciding how to counteract the disturbance.
6 0
3 years ago
A 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, what
ludmilkaskok [199]

The initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C

<h3>How to calculate temperature?</h3>

The initial temperature of the copper metal can be calculated using the following formula on calorimetry:

Q = mc∆T

mc∆T (water) = - mc∆T (metal)

Where;

  • m = mass
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C. If the final temperature of water is 42.0 °C, the initial temperature of the copper is as follows:

400 × 4.18 × (42°C - 24°C) = 240 × 0.39 × (T - 24°C)

30,096 = 93.6T - 2246.4

93.6T = 32342.4

T = 345.5°C

Therefore, the initial temperature of the copper piece if a 240.0 gram piece of copper is dropped into 400.0 grams of water at 24.0 °C is 345.5°C.

Learn more about temperature at: brainly.com/question/15267055

8 0
2 years ago
What is considered to be an unsafe level of lead in flint michigan water?
Olenka [21]

Answer:

More than 40 percent measured above 5 ppb of lead, which the researchers considered an indication of a “very serious” problem.

7 0
3 years ago
What is the molarity of a 3.0 solution of magnesium chloride prepared with 9.0 molecules of MgCl2 A. 6.0 M B. 3.0 M C. 27.0 M D.
Gala2k [10]

Answer:

Option B. 3.0 M

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 3.0 L

Mole of MgCl₂ = 9 moles

Molarity =?

Molarity can simply be defined as the mole of solute per unit litre of the solution. Mathematically, it can be expressed as:

Molarity = mole of solute /Volume of solution

With the above formula, we can obtain the molarity of the solution as follow:

Volume of solution = 3.0 L

Mole of MgCl₂ = 9 moles

Molarity =?

Molarity = mole of solute /Volume of solution

Molarity = 9 / 3

Molarity = 3 mol/L = 3.0 M

Thus, the molarity of the solution is 3 M

8 0
3 years ago
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