Answer:
4.90 g
Explanation:
Given that:
volume of t-pentyl alcohol = 5 mL
the standard density of t-pentyl alcohol = 0.805 g/mL
Recall that:
density = mass(in wt) /volume
mass = density × volume
mass = 0.805 g/mL × 5 mL
mass = 4.03 g
Volume of HCl used = 12 mL
The reaction for this equation is shown in the image attached below.
From the reaction,
88.15 g of t-pentyl alcohol reacts with concentrated HCl to yield 106.59 g pf t-pentyl chloride.
4.03 g of t-pentyl alcohol forms,
of t-pentyl chloride.
Therefore,
Theoretical yield of t-pentyl chloride = 4.90 g
Answer: 25%
Explanation: According to the Florida Industrial and Phosphate Research Institute, Florida’s phosphate mining accounts for about 75% of the phosphate used in the United States, as well as about 25% phosphate used around the world. Although first mined in England in 1847, and used as fertilizer, In 1881, a civilian employee, J Francis Le Baron discovered Phosphate pebbles in peace river, and then, a hard rock phosphate district was discovered in north central Florida after that which began the Phosphate mining industry in Florida. Phosphorus rock supplies the phosphorus element in the fertilizer mix of nitrogen-phosphorus-potassium that is used as fertilizer to aid in growth of plants.
Answer: 22 grams because mass cannot be created or destroyed
Explanation: I just took the test
Answer:
The answer to your question is 22.4 g of Ca(NO₃)₂
Explanation:
Data
mass of Ca(NO₃)₂ = ?
mass of water = 726 g
concentration = 0.2 m
Process
In Chemistry, there are two main units of concentration Molarity (M) and Molality (m). In this problem concentration is "m" then I will calculate molality.
1) Formula
molality = moles / mass of solvent
2.- Solve for moles
moles = molality x mass of solvent
-Substitution
moles = (0.2) x (0.726)
-Simplification
moles = 0.1452
3.- Convert moles to grams
Molar mass of Ca(NO₃)₂ = 40 + (14 x 2) + (6 x 16)
= 40 + 18 + 96
= 154 g
154 g of Ca(NO₃)₂ ---------------- 1 mol
x ---------------- 0.1452 moles
x = (0.1452 x 154) / 1
x = 22.4 g of Ca(NO₃)₂