Answer:
The solution is given in the attachments.
Answer:
0.25 J/K
Explanation:
Given data in given question
heat (Q) = 100 J
temperature (T) = 400 K
to find out
the change in entropy of the given system
Solution
we use the entropy change equation here i.e
ΔS = ΔQ / T ...................a
Now we put the value of heat (Q) and Temperature (T) in equation a
ΔS is the entropy change, Q is heat and T is the temperature,
so that
ΔS = 100/400 J/K
ΔS = 0.25 J/K
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Answer:
A private plane pilot is a mid-level position.
Explanation:
The six pilot certifications in the US are as follows:
- Sport Pilot
- Recreational Pilot
- Private Plane Pilot
- Commercial Plane Pilot
- Flight Instructor
- Airline Transport Pilot
From this listing, it is evident that the Private Plane Pilot is in the mid of the line so it is a mid-level position.
Answer:Yes,266.66 MPa
Explanation:
Given
Yield stress of material =140 MPa
Cross-section of 
Force(F)=8 MN
Therefore stress due to this Force(
)
Since induced stress is greater than Yield stress therefore Plastic deformation occurs
