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defon
2 years ago
11

Which of theCardiorespiratory fitness is most likely to improve due to which of the following types of exercise? A. bicycling B.

weight lifting C. push-ups D. sit-ups Please select the best answer from the choices provided. A B C D
Chemistry
1 answer:
gizmo_the_mogwai [7]2 years ago
7 0

Answer: A (Bicycling)

Explanation:

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How do I find the number of moles and molar mass of Gas A and Gas B with the information provided?
drek231 [11]

Answer:

A.

Explanation:

hope this helped sorry if its wrong!

3 0
3 years ago
oils will dissolve best in solvents that are? A. polar B. nonpolar C. either polar or nonpolar D. neither polar nor nonpolar
Genrish500 [490]
The answer is <span>B. nonpolar.

Polar molecules dissolve best in polar solvents while nonpolar molecules dissolve best in nonpolar solvents. </span>Oils are nonpolar. So, they will dissolve best in nonpolar solvents. If you put oil in some polar solvent, such as water, it will hardly dissolve.
4 0
3 years ago
Suggest the identity of the gas in the bubbles ​
Vlad1618 [11]

Answer:

<h3>it is hydrogen gas </h3>

3. the chemical equation is :

MgSO4 ( s ) + H2SO4 (aq)-->

MgSO4 (aq) + CO2 (g) + H2O (I)

THE IONISING OF H2SO4 IN SOLUTION IS CONPLEX

4. MAGNESIUM REACTION WITH DILUTE SULPHURIC ACID TO FORM

MAGNESIUM SULPHATE AND HYDROGEN GAS

Explanation:

hope it helps u

7 0
3 years ago
Read 2 more answers
The pH of a 1.0M solution of butanoic acid HC4H7O2 is measured to be 2.41. Calculate the acid dissociation constant Ka of butano
Lubov Fominskaja [6]

Answer:

Ka = 1.52 E-5

Explanation:

  • CH3-(CH2)2-COOH ↔ CH3(CH2)2COO-  + H3O+

⇒ Ka = [H3O+][CH3)CH2)2COO-] / [CH3(CH2)2COOH]

mass balance:

⇒<em> C</em> CH3(CH2)2COOH = [CH3(CH2)2COO-] + [CH3(CH2)2COOH] = 1.0 M

charge balance:

⇒ [H3O+] = [CH3(CH2)2COO-]

⇒ Ka = [H3O+]²/(1 - [H3O+])

∴ pH = 2.41 = - Log [H3O+]

⇒ [H3O+] = 3.89 E-3 M

⇒ Ka = (3.89 E-3)² / ( 1 - 3.89 E-3 )

⇒ Ka = 1.519 E-5

3 0
3 years ago
Consider a sample of a hydrocarbon (a compound consisting of only carbon and hydrogen) at 0.959 atm and 298 K. Upon combusting t
Masja [62]

Answer:

Molecular formula of hydrocarbon is: C₂H₆

Explanation:

The combusting of the hydrocarbon:

CxHy + O₂ → CO₂ + H₂O

Using gas law to obtain molar mass of the gas mixture (CO₂ + H₂O):

P/RT = n/V

Where:

P is pressure (1,208 atm)

R is gas constant (0,082 atmL/molK)

T is temperature (375 K)

n/V = 0,0393 mol/L

1,1128 g/L ÷ 0,0393 mol/L = 28,32 g/mol

Thus, average molecular weight is:

28,32 g/mol = 44,01 g/mol X + 18,02 g/mol Y

1 = X + Y

Where X is CO₂ molar percentage and Y is H₂O molar percentage.

Solving:

X = 0,397

Y = 0,603

39,7% H₂O

60,3% CO₂

With this proportion you can obtain ratio CO₂:H₂O thus:

60,3/39,7 = 1,52 So, 2 CO₂: 3H₂O

The moles of the hydrocarbon are:

PV/RT = n

P (0,959 atm)

V ( 1/5 of final volume)

T (298K)

n = 7,85x10⁻³ mol

The moles of CO₂ are:

0,0393 mol × 2 mol CO₂/ 5 mol total =0,01572.

Ratio of CO₂:CxHY =

0,01572 : 7,85x10⁻³ 2 CO₂: 1 CxHY

Doing:

1 CxHy + O₂ → 2 CO₂ + 3 H₂O

By mass balance:

1 C₂H₆ + 7/2 O₂  → 2 CO₂ + 3 H₂O

Thus, molecular formula of hydrocarbon is: <em>C₂H₆ </em>

I hope it helps!

7 0
3 years ago
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