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gladu [14]
3 years ago
11

Jeremy ran a race at a speed of 15 m/s in a time of 8 seconds. Calculate the distance he ran.

Physics
2 answers:
Masja [62]3 years ago
8 0

Answer:

120 m/s if m/s means miles per second than

Explanation:

15 × 8

Damm [24]3 years ago
6 0

Answer:

d = 120 m

Explanation:

Data:

  • Speed (s) = 15 m/s
  • Time (t) = 8 s
  • Distance (d) = ?

Use the formula:

  • d = s * t

Replace with the data, and solve:

  • d = 15 m/s * 8 s
  • d = 120 m

The distance is 120 meters.

Greetings.

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Two rams run toward each other. One ram has a mass of 49 kg and runs west
olga nikolaevna [1]

Answer: (d)

Explanation:

Given

Mass of the first ram m_1=49\ kg

The velocity of this ram is v_1=-7\ m/s

Mass of the second ram m_2=52\ kg

The velocity of this ram v_2=9\ m/s

They combined after the collision

Conserving the momentum

\Rightarrow m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow 49\times (-7)+52\times (9)=(52+49)v\\\Rightarrow v=\dfrac{125}{101}\ m/s \quad[\text{east}]

Momentum after the collision will be

\Rightarrow 101\times \dfrac{125}{101}=125\ kg-m/s\ \text{East}

Therefore, option (d) is correct

4 0
3 years ago
Which does not contain a lens?
denis23 [38]
Im pretty sure it’s A eye
8 0
3 years ago
Differentiate between center of mass and center of gravity
ELEN [110]

Answer:

Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.

Explanation:

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3 0
3 years ago
How many degrees are in each quadrant <br> A: 90°<br> B: 30°<br> C: 180°<br> D: 360°
Airida [17]

In one quadrant there are 90 degrees.

8 0
3 years ago
A fixed 11.2-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.10 s , the field is changed to
Karolina [17]

Answer:

The average induced emf in the coil is 0.0286 V

Explanation:

Given;

diameter of the wire, d = 11.2 cm = 0.112 m

initial magnetic field, B₁ = 0.53 T

final magnetic field, B₂ = 0.24 T

time of change in magnetic field, t = 0.1 s

The induced emf in the coil is calculated as;

E = A(dB)/dt

where;

A is area of the coil = πr²

r is the radius of the wire coil = 0.112m / 2 = 0.056 m

A = π(0.056)²

A = 0.00985 m²

E = -0.00985(B₂-B₁)/t

E = 0.00985(B₁-B₂)/t

E = 0.00985(0.53 - 0.24)/0.1

E = 0.00985 (0.29)/ 0.1

E = 0.0286 V

Therefore, the average induced emf in the coil is 0.0286 V

3 0
3 years ago
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