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patriot [66]
3 years ago
10

Warm air rising is part of a __________________________ current.

Physics
1 answer:
adelina 88 [10]3 years ago
4 0

Answer:

Thermal

Explanation:

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How much force is needed to slow down a 15 kg car traveling at 60 m/s to 15 m/s in 10 seconds?​
goldfiish [28.3K]

Answer:

The force needed to slow down the car is, F = 67.5 N

Explanation:

Given data,

The mass of the car, m = 15 kg

The initial velocity of the car, V = 60 m/s

The final velocity of the car, v = 15 m/s

The time period of deceleration, t = 10 s

The difference in the momentum of the car is,

                                     mV - mv = 15(60 - 15)

                                                    = 675 kg m/s

The rate of change in momentum of the car gives the force acting on it.

                                    F = (mV - mu) / t

Substituting the values,

                                   F = 675 / 10

                                      = 67.5 N

Hence, the force needed to slow down the car is, F = 67.5 N

3 0
4 years ago
What is the change in internal energy if 30 J of thermal energy is released
alexira [117]

Answer:

ΔU = -70 J

Explanation:

ΔU = Q − W

where ΔU is the change in internal energy,

Q is the heat absorbed by the system,

and W is the work done by the system (on the surroundings).

30 J of thermal energy is released, so Q = -30 J.

40 J of work is done by the system, so W = 40 J.

Therefore, the change in internal energy is:

ΔU = -30 J − 40 J

ΔU = -70 J

6 0
3 years ago
How do you find displacement when all you have is time with no velocity, and then in order to find velocity you have to have dis
saw5 [17]
If you really have nothing else but time, then you can't. There must be some other shred of information. Search around. Look under rocks.
3 0
4 years ago
The greenhouse effect is
klio [65]
It a because I learn it in class today
6 0
3 years ago
Read 2 more answers
If the length of a building is 2 1 2 times the width and each dimension is increased by 7 ft, then the perimeter is 266 ft. Find
N76 [4]

Answer:

The original dimensions of the building is 95 ft × 38 ft.

Explanation:

Let the original length be 'l' and original width be 'w'.

Given:

Original length (l) = 2\frac{1}{2}\times original\ width

Original width = 'w'.

So, l=2\frac{1}{2}w=\frac{5}{2}w

Now, as per question:

Length and width is increased by 7 ft.

So, new length (l') = l+7=\frac{5w}{2}+7

New width (w') = w+7

New perimeter (P) = 266 ft

Perimeter is given as:

P=2(l' +w')\\\\266=2(\frac{5w}{2}+w)\\\\\frac{266}{2}=\frac{5w+2w}{2}\\\\266=7w\\\\w=\frac{266}{7}=38\ ft

Therefore, original width = 38 ft.

Original length is, l=\frac{5\times 38}{2}=\frac{190}{2}=95\ ft

Hence, the original dimensions of the building is 95 ft × 38 ft.

7 0
4 years ago
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