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3 years ago

Write word equations for these reactions: (a) Zn + Cuso, → ZnSO, + Cu CuSO4

Chemistry

1 answer:

kobusy [5.1K]3 years ago

4 0

Answer:

Zinc + Copper Sulfate -> Zinc Sulfate + Copper Sulfate

cusO4 = Copper Sulfate

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A4 g sugar cube (Sucrose : C 12 H 22 O 11 ) is dissolved in a 350 ml teacup of 80 C water. What is the percent composition by ma

lana66690 [7]

Answer:

%Sgr = 1% (1 sig.fig.)

Explanation:

mass water = 350ml x 0.975g/ml = 341.25g

mass sugar added = 4g

solution mass = 341.25g + 4g = 345.25g

%sugar = (4g/345.25g)·100% = 1.1586% ≅ 1% (1 sig.fig)

7 0

3 years ago

For the following reaction in aqueous solution, identify all those species that will be spectator ions. Select all that apply.

uranmaximum [27]

The reaction is incorrect. The correct reaction is: Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃. The options are:

A. Hg₂SO₄

B. Na₂SO₄

C. Na⁺

D. NO₃⁻

E. SO₄⁻²

F. Hg₂(NO₃)₂

G. NaNO₃

H. Hg⁺²

Answer:

C, D, E, H

Explanation:

The ions are formed after dissociation of the compound in the solution. When they're negatively charged, they're called anions, when they're negatively charged, they're called cations. If the ion is presented on both sides of the reaction, it is called a spectator ion.

Thus, the reaction given:

Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃

So, let's do the dissociation.

Na₂SO₄ is formed by the ions Na⁺ and SO₄⁻²;

Hg(NO₃)₂ is formed by the ions Hg⁺² and NO₃⁻;

HgSO₄ is formed by the ions Hg⁺² and SO₄⁻²;

NaNO₃ is formed by the ions Na⁺ and NO₃⁻.

Thus, the spectator ions are Na⁺, SO₄⁻², Hg⁺², and NO₃⁻.

7 0

4 years ago

What volume of hydrogen is necessary to react with 6.25g of nitrogen to produce ammonia?

Dovator [93]

A.30L First one the answer

7 0

3 years ago

Read 2 more answers

14. How is the number of neutrons in the nucleus of an atom calculated?

grin007 [14]

Subtract the number of protons from the mass number.

7 0

4 years ago

Se combustionan 2 g de magnesio en Aire, obteniéndose 3,28 g de óxido de magnesio (MgO)¿Qué masa de oxígeno se consumen en la re

konstantin123 [22]

Answer:

1.30 g

Explanation:

La reacción que toma lugar es:

2Mg + O₂ → 2MgO

Primero convertimos 3.28 g de MgO en moles, usando su masa molar:

3.28 g ÷ 40.3 g/mol = 0.081 mol MgO

Después convertimos 0.081 moles de MgO en moles de O₂, usando los coeficientes estequiométricos:

0.081 mol MgO * $\frac{1molO_2}{2molMgO}$ = 0.0407 mol O₂

Finalmente convertimos 0.0407 moles de O₂ en gramos:

0.0407 mol O₂ * 32 g/mol = 1.30 g

5 0

3 years ago