Toichiometry time! Remember to look at the equation for your molar ratios in other problems.
31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag 6851.65⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ → ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻ = 107.9 g Ag ∅ | 63.5 g Cu | 1 mol Cu | 1 mol Ag 63.5
There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.
Answer: 850.0 g/min.
Explanation:
- The rate of the reaction = (ΔC/Δt) where,
ΔC is the change in concentration of reactants or products.
Δt is the change in time of the reaction proceeding.
- The rate is needed to be calculated in (g/min).
- We need to calculate the amount of the product in (g) via using the relation (n = mass / molar mass).
- mass (g) = n x molar mass,
- n = 1.5 moles and molar mass of P₄O₁₀ = 283.88 g/mol.
- m = 1.5 x 283.88 = 425.82 g.
- ΔC = 425.82 g and Δt = 30 s / 60 = 0.5 min.
- The rate of the reaction = ΔC / Δt = (425.82 g / 0.5 min) = 851.64 g/min.
<em>can be approximated to 850.0 g/min.</em>
Decay constant, proportionality between the size of a population of radioactive atoms and the rate at which the population decreases because of radioactive decay.
<h3>What is decay constant value?</h3>
The rate of disintegration is proportional to the number of atoms at any point in time and the constant of proportionality is called the radioactivity decay constant. The radioactive decay constant for Radium B is approximately 4.3 × 10−4 s−1.
<h3>What is decay constant unit?</h3>
Definition. The decay constant (symbol: λ and units: s−1 or a−1) of a radioactive nuclide is its probability of decay per unit time. The number of parent nuclides P therefore decreases with time t as dP/P dt = −λ. The energies involved in the binding of protons and neutrons by the nuclear forces are ca.
Learn more about decay constant here:
<h3>
brainly.com/question/16623902</h3><h3 /><h3>#SPJ4</h3>
Answer : The correct option is, (3) Oxidation occurs at the anode and reduction occurs at the cathode.
Explanation :
Electrochemical cell : It is a type of device which is used to convert the chemical energy into electrical energy during the redox reaction.
In the electrochemical cell, there are two electrodes. The electrode on which the oxidation takes place is called the anode (or negative pole) and the electrode on which the reduction takes place is called the cathode (or positive pole). This cell is connected by the salt bridge.
In the external circuit, the electrons flow from the anode (negative pole) to cathode (positive pole) through the voltmeter.
In the inner circuit, the ions flow through the salt bridge.
Hence, the correct option is, (3) Oxidation occurs at the anode and reduction occurs at the cathode.
Thermal expansion causes the gas particles inside the ping pong ball to spread apart, putting pressure on the dent and popping back out.
