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boyakko [2]
3 years ago
5

Which sample is a pure substance?zinc oxidesugar dissolved in waterpond watersoil.

Chemistry
1 answer:
AnnZ [28]3 years ago
6 0

Answer:

Oxide sugar dissolved in water pond

because water + sugar= sugar melts but the oxide purifys the water.

Explanation:

<u><em>#carryonlearning!</em></u>

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Complete the sentences to explain why the lattice energy of potassium bromide is more exothermic than the lattice energy of rubi
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The lattice energy is the amount of energy released when the ions that make up a crystal lattice are brought together. Now, this energy is dependent on the charge concentration of these ions. Both potassium and rubidium form ions with a +1 charge, while bromine and iodine form ions with -1 charge. However, because potassium and bromine are smaller than rubidium and iodine respectively, the charge is more concentrated. Therefore, more energy is released when potassium and bromine are brought together. 
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If the cost of electricity is 8 cents/kWh, how much will it cost to use the light for a whole year (365 days)?
bearhunter [10]

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$13.8

Explanation:

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When 2.85 moles of chlorine reacts with excess tin, how many moles of tin choloride are formed?
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chlorine by twenty øne piløts

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Calcula la masa equivalente del clorato de calcio CA (CI03)2
Vitek1552 [10]

Answer:

207g

Explanation:

Given compound:

            Ca(ClO₃)₂

Equivalent mass is the

The equivalent mass can be derived by summing the molar masses of each atom

  Molar mass of Ca = 40

                            Cl  = 35.5

                            O  = 16

Now solve;

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6 0
3 years ago
Please help
KonstantinChe [14]

Answer:  There are 0.5 grams of barium sulfate are present in 250 of 2.0 M BaSO_{4} solution.

Explanation:

Given: Molarity of solution = 2.0 M

Volume of solution = 250 mL

Convert mL int L as follows.

1 mL = 0.001 L\\250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L

Molarity is the number of moles of solute present in liter of solution. Hence, molarity of the given BaSO_{4} solution is as follows.

Molarity = \frac{mass}{Volume (in L)}\\2.0 M = \frac{mass}{0.25 L}\\mass = 0.5 g

Thus, we can conclude that there are 0.5 grams of barium sulfate are present in 250 of 2.0 M BaSO_{4} solution.

7 0
3 years ago
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