Answer:
pH = 11.9
Explanation:
First, we <u>determine the number of OH⁻ moles dissolved</u>:
<em>80% of Ca(OH)₂ is dissolved</em>:
- 0.0005 mol * 80/100 = 4x10⁻⁴ mol Ca(OH)₂
<em>There are two OH⁻ moles per Ca(OH)₂ mol</em>:
- 4x10⁻⁴ * 2 = 8x10⁻⁴ mol OH⁻
Now we can <u>calculate the molar concentration of OH⁻</u> (moles/L):
- 100 mL ⇒ 100/1000 = 0.1 L
- [OH⁻] = 8x10⁻⁴ mol / 0.1 L = 8x10⁻³ M
Then we <u>calculate the pOH of the solution</u>:
- pOH = -log[OH⁻] = -log(8x10⁻³ M) = 2.10
Finally, we can <u>calculate the pH of the solution</u> using the equation
Combustible more specific answer chemical reaction
Answer:
79'420J
Explanation:
We know mass 250g and
∆T=98°C -22°C
=76°C
The specific heat capacity for water is 4,18Zj/g°C
THEREFORE
∆H=250g•14,8j/g°C •76°C
=79'420J