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vagabundo [1.1K]
2 years ago
10

what is the largest, low-cost airline carrier in the world, which recently canceled thousands of flights for reasons partially d

isputed by the federal aviation administration?
Engineering
1 answer:
IgorC [24]2 years ago
8 0

The largest, low-cost airline carrier in the world that recently canceled thousands of flights for reasons partially disputed by the federal aviation administration (FAA) is Southwest Airlines.

Southwest Airlines canceled 2,500 flights in just a few days.

According to Southwest Airlines, the cause of the cancellation is due to air traffic control problems and disruptive weather.

While FAA claimed that nothing like a reported case of air traffic and staffing shortages.

Southwest Airlines is the world's largest low-cost carrier and has its main office is located in Dallas, Texas.

Hence, in this case, it is concluded that the correct answer is "Southwest Airlines."

Learn more here: brainly.com/question/24782945

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A piston-cylinder device contains 0.15 kg of air initially at 2 MPa and 350 °C. The air is first expanded isothermally to 500 kP
Semmy [17]

Answer:

Isothermal  expansion W₁ =-37198.9 J

Polytropic Compression W₂ =-34872.82 J

Isobaric Compression W₃ =  -6974.566 J

The net work for the cycle = -79046.29 J

Explanation:

Mass of air = 0.15 kg = 150 g

Molar mass = 28.9647 g/mol

Number of moles = 150 g /28.9647 g/mol = 5.179 moles of air

PV = nRT therefrore V = nRT/(P) = 5.179*8.314*(350+273.15)/(2×10⁶) = 0.0134167 m³

For isothermal expansion we have

P₁V₁ = P₂V₂ or V₂ = P₁V₁/P₂ = 2×10⁶*0.0134167 / (5×10⁵) = 0.0536668 m³

Therefore work done

W₁ = -nRTln(V₂/V₁) = -26833ln(4) = -37198.9 J

Stage 2

Compression polytropically we have

\frac{P_2}{P_3} = (\frac{V_3}{V_2} )^n  where P₃ = 2 MPa

Therefore V₃ = (\frac{1}{4} )^{\frac{1}{1.2} }*V_2  = 1.6904×10⁻² m³

Work = W₂ = \frac{P_2V_2-P_3V_3}{n-1} =  -34872.82 J

\frac{P_2}{P_3} = (\frac{T_2}{T_3} )^\frac{n}{n-1}     or T₃ = T_2*(\frac{P_3}{P_2})^\frac{n-1}{n} = 785.12 K

Isobaric compression we have  thus

Work done W₃ = P(V₁ -V₃) = -6974.566 J

Total work = W₁ + W₂ + W₃ = -37198.9 J + -34872.82 J + -6974.566 J = -79046.29 J

7 0
2 years ago
Some_____
Thepotemich [5.8K]

Answer:

it’s IGS

Explanation:

because i read

5 0
3 years ago
I will give Brainliest, please help. :)
ziro4ka [17]

Answer:

The ratio of water to flour needed to make tortillas, which is 3 : 4

Explanation:

100 w = 75 f

w/f = 75/100 = 3/4

7 0
2 years ago
Read 2 more answers
An AC generator supplies an rms voltage of 120 V at 50.0 Hz. It is connected in series with a 0.650 H inductor, a 4.80 μF capaci
Serggg [28]

Answer:

Explanation:

f = 50.0 Hz, L = 0.650 H, π = 3.14

C = 4.80 μF, R = 301 Ω resistor. V = 120volts

XL = wL = 2πfL

= 2×3.14×50* 0.650

= 204.1 Ohm

Xc= 1/wC

Xc = 1/2πfC

Xc = 1/2×3.14×50×4.80μF

= 1/0.0015072

= 663.48Ohms

1. Total impedance, Z = sqrt (R^2 + (Xc-XL)^2)= √ 301^2+ (663.48Ohms - 204.1 Ohm)^2

√ 90601 + (459.38)^2

√ 90601+211029.98

√ 301630.9844

= 549.209

Z = 549.21Ohms

2. I=V/Z = 120/ 549.21Ohms =0.218Ampere

3. P=V×I = 120* 0.218 = 26.16Watt

Note that

I rms = Vrms/Xc

= 120/663.48Ohms

= 0.18086A

4. I(max) = I(rms) × √2

= 0.18086A × 1.4142

= 0.2557

= 0.256A

5. V=I(max) * XL

= 0.256A ×204.1

=52.2496

= 52.250volts

6. V=I(max) × Xc

= 0.256A × 663.48Ohms

= 169.85volts

7. Xc=XL

1/2πfC = 2πfL

1/2πfC = 2πf× 0.650

1/2×3.14×f×4.80μF = 2×3.14×f×0.650

1/6.28×f×4.8×10^-6 = 4.082f

1/0.000030144× f = 4.082×f

1 = 0.000030144×f×4.082×f

1 = 0.000123f^2

f^2 = 1/0.000123048

f^2 = 8126.922

f =√8126.922

f = 90.14 Hz

8 0
3 years ago
Select the correct answer.<br> Which equation gives you the amount of work performed?
Fantom [35]

Answer:

Hello

this is the answer

5 0
3 years ago
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