Answer:
see explaination
Explanation:
import java.util.InputMismatchException;
import java.util.Scanner;
public class calculate {
static float a=0,b=0;
double cal()
{
if(a==0||b==0)
{
System.out.println("no values found in a or b");
start();
}
double x=(a*a)+(b*b);
double h=Math.sqrt(x);
a=0;
b=0;
return h;
}
float enter()
{
float val=0;
try
{
System.out.println("Enter side");
Scanner sc1 = new Scanner(System.in);
val = sc1.nextFloat();
return val;
}
catch(InputMismatchException e)
{
System.out.println("Enter correct value");
}
return val;
}
void start()
{
calculate c=new calculate();
while(true)
{
System.out.println("Enter Command");
Scanner sc = new Scanner(System.in);
String input = sc.nextLine();
switch(input)
{
case "A":
a=c.enter();
break;
case "B":
b=c.enter();
break;
case "C":
double res=c.cal();
System.out.println("Hypotenuse is : "+res);
break;
case "Q":
System.exit(0);
default:System.out.println("wrong command");
}
}
}
public static void main(String[] args) {
calculate c=new calculate();
c.start();
}
}
Answer:
the correct distance is 202 ft
Explanation:
The computation of the correct distance is shown below:
But before that correction to be applied should be determined
= (101 ft - 100 ft) ÷ (100 ft) × 200 ft
= 2 ft
Now the correct distance is
= 200 ft + 2 ft
= 202 ft
Hence, the correct distance is 202 ft
The same would be relevant and considered too
Answer:
474.59 mg/L
Explanation:
Given that
BOD = 30 mg/L
Original BOD = 30 mg/L × dilution factor
Original BOD = 30 mg/L × 10 = 300 mg/L
here 
is the ultimate BOD ; BOD is the biochemical oxygen demand ; t = 0.20 /day
Explanation:
Outer di ameter ![d_{0}=400 \mathrm{mm}[tex] Thickness of the cylinder [tex]t=10 \mathrm{mm}](https://tex.z-dn.net/?f=d_%7B0%7D%3D400%20%5Cmathrm%7Bmm%7D%5Btex%5D%20Thickness%20of%20the%20cylinder%20%5Btex%5Dt%3D10%20%5Cmathrm%7Bmm%7D)
![\therefore[tex] Inner diam eter [tex]d_{i}=d_{0}-2 t=400-2 \times 10](https://tex.z-dn.net/?f=%5Ctherefore%5Btex%5D%20Inner%20diam%20eter%20%5Btex%5Dd_%7Bi%7D%3Dd_%7B0%7D-2%20t%3D400-2%20%5Ctimes%2010)
Given loading on the cylinder 
Helix an gle of the weld form 
(i) Normal stress on the plane at angle is
(ii) Shear stress along an angle of is 
