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3 years ago

Using Java..

Engineering

1 answer:

uysha [10]3 years ago

7 0

Answer:

The source code files for this question have been attached to this response.

Please download it and go through each of the class files.

The codes contain explanatory comments explaining important segments of the codes, kindly go through these comments.

Download java

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What substance does light travel through before putting water in the cup

torisob [31]

Bend surface in water! Hopefully this helps, I looked it up!

6 0

3 years ago

"All data types are keywords but all keywords are not data types", justify this statement.

STALIN [3.7K]

<h3>Hey Mate Here Is Your Answer</h3>

Keywords Are Reserved Words Which Are Not Use As Normal Cases But Used For Special Purpose In Our Program whereas, Data Type Tells The Compiler And Interpreter How The Program Is Going To Be Executed And Can Be Used At Every Cases.

<h3>Hope This Helps You ❤️</h3>

5 0

3 years ago

Write a SELECT statement that returns the same result set as this SELECT statement, but don’t use a join. Instead, use a subquer

Bess [88]

Answer:

See explanation

Explanation:

The complete question is

Write a SELECT statement that returns the same result set as this SELECT statement, but don't use a

join. Instead, use a subquery in a WHERE clause that uses the IN keyword.

SELECT DISTINCT category_name

FROM categories c JOIN products p

ON c.category_id = p.category_id

ORDER BY category_name

The join clause gives us all the registers of both tables, for which the category_id of categories coincides to the category_id in the table products. That is, we can first select the distinct category_id's from products and the see the categories from categories table, whose id is in that list. That means writing the following query:

Select distinct category_name

from categories c

where c.category_id in (

select distinct p.category_id

from products p)

order by category_name

4 0

4 years ago

A cylindrical specimen of cold-worked steel has a Brinell hardness of 250.(a) Estimate its ductility in percent elongation.(b) I

koban [17]

Answer:

A) Ductility = 11% EL

B) Radius after deformation = 4.27 mm

Explanation:

A) From equations in steel test,

Tensile Strength (Ts) = 3.45 x HB

Where HB is brinell hardness;

Thus, Ts = 3.45 x 250 = 862MPa

From image 1 attached below, for steel at Tensile strength of 862 MPa, %CW = 27%.

Also, from image 2,at CW of 27%,

Ductility is approximately, 11% EL

B) Now we know that formula for %CW is;

%CW = (Ao - Ad)/(Ao)

Where Ao is area with initial radius and Ad is area deformation.

Thus;

%CW = [[π(ro)² - π(rd)²] /π(ro)²] x 100

%CW = [1 - (rd)²/(ro)²]

1 - (%CW/100) = (rd)²/(ro)²

So;

(rd)²[1 - (%CW/100)] = (ro)²

So putting the values as gotten initially ;

(ro)² = 5²([1 - (27/100)]

(ro)² = 25 - 6.75

(ro) ² = 18.25

ro = √18.25

So ro = 4.27 mm

6 0

4 years ago

Determine the maximum volume in gallons [gal] of olive oil that can be stored in a closed cylindrical silo with a diameter of 3

Olin [163]

Answer:

V=1601gal

Explanation:

Hello! This problem is solved as follows,

First we must raise the equation that defines the pressure at the bottom of the tank with the purpose of finding the height that olive oil reaches.

This is given as the sum due to the atmospheric pressure (1atm = 101.325kPa), and the pressure due to the weight of the olive oil, taking into account the above, the following equation is inferred.

P=Poil+Patm

P=total pressure or absolute pressure=26psi=179213.28Pa

Patm= the atmospheric pressure =101325Pa

Poil=pressure due to the weight of olive oil=0.86αgh

α=density of water=1000kg/m^3

g=gravity=9.81m/s^2

h= height that olive oil reaches

solving

P=Poil+Patm

P=Patm+0.86αgh

$h=\frac{P-Patm}{0.86\alpha g } =\frac{179214.28-101325}{(0.86)(1000)(9.81)} \\h=9.23m$ [/tex]

Now we can use the equation that defines the volume of a cylinder.

V= $V=\frac{\pi }{4} D^{2} h$

D=3ft=0.9144m

h=9.23m

solving

$V=\frac{\pi }{4} (0.9144)^{2} 9.23=6.06m^3$

finally we use conversion factors to find the volume in gallons

$V=6.06m^3\frac{1000L}{1m^3} \frac{1gal}{3.785L} =1601gal$

3 0

4 years ago