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3 years ago

Using Java..

Engineering

1 answer:

uysha [10]3 years ago

7 0

Answer:

The source code files for this question have been attached to this response.

Please download it and go through each of the class files.

The codes contain explanatory comments explaining important segments of the codes, kindly go through these comments.

Download java

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Answer:

mechanical engineer is the best answer

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3 years ago

To reduce the negative impacts of stress on your mental

soldi70 [24.7K]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

A 2-mm-diameter electrical wire is insulated by a 2-mm-thick rubberized sheath (k = 0.13 W/m K), and the wire/sheath interface i

Semmy [17]

Answer:

maximum allowable electrical power=4.51W/m

critical radius of the insulation=13mm

Explanation:

Hello!

To solve this heat transfer problem we must initially draw the wire and interpret the whole problem (see attached image)

Subsequently, consider the heat transfer equation from the internal part of the tube to the external air, taking into account the resistance by convection, and conduction as shown in the attached image

to find the critical insulation radius we must divide the conductivity of the material by the external convective coefficient

$r=\frac{k}{h} =\frac{0.13}{10}=0.013m=13mm$

3 0

3 years ago

A plane, opaque, surface M has the following properties: gray, diffuse, absorptivity = 0.7, surface area = 0.5 m2 , temperature

BaLLatris [955]

Answer:

The rate of energy absorbed per unit time is 3500W.

Explanation:

From the question, we were given the following parameters;

Plane, opaque, gray, diffuse surface

â = 0.7

Surface area, A = 0.5m²

Incoming radiant energy, G = 10000w/m²

T = 500°C

Rate of energy absorbed is âAG;

âAG = 0.7 × 0.5 × 10000

âAG = 3500W.

The energy absorbed is measured in watts and denoted by the symbol W.

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3 years ago

To produce cooling the refrigerant much

lawyer [7]

Yes that is correct good job ❤️

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4 years ago