All categories

3 years ago

To reduce the negative impacts of stress on your mental

Engineering

2 answers:

soldi70 [24.7K]3 years ago

4 0

Answer:

A&C

Explanation:

breathing deeply is relaxing

talking with a friend can helping

neonofarm [45]3 years ago

4 0

Answer:

A & C

Explanation:

Talking with a friend can help unload the stress you have and breathing deeply can help you relax. Ignoring your body will just make stress worse.

You might be interested in

A flow of 2.6 MGD leaves a primary clarifier with a BOD of 131 mg/L. Determine the aeration period (hydraulic detention time) of

SashulF [63]

Answer:

8.5 days

Explanation:

Given data :

Flow ( Q ) = 2.6 MGD = 11819.834 m^3/day

BOD = 131 mg/L

BOD loading rate = 35 Ibs/1000 ft^3 per day = 0.5606 kg/m^3/day

<u>Calculate the sludge age of the facility </u>

Given the BOD applied to the aeration tank = 11819.834 m^3/day * 131mg/l

= 1548.398 kg/day

first calculate the volume of the aeration tank

V = BOD applied / BOD loading rate

V = 1548.398 / 0.5606 = 2762.03 m^3

Hydraulic Detention time = V / Q

= 2762.03 / 11819.834 = 0.2336 day = 5.6 hour

next : determine the mass rate of the waste

= 44% * 0.5606 kg/m^3/day

= 0.2466 kg/m^2/day

finally determine the sludge age

= V * Xt / ∅w * R

= ( 2762.03 m^3 * 2100 * 10^-3 ) / ( 0.2466 * 2762.03 kg/day )

= 8.5 days

8 0

3 years ago

A hollow steel shaft with and outside diameter of (do)-420 mm and an inside diameter of (di) 350 mm is subjected to a torque of

-Dominant- [34]

Answer:

a. $\tau=51.55 MPa$

b. $\tau=42.95MPa$

c. $\theta=7.67\times 10^{-3}$ rad.

Explanation:

Given: $D_i=350 mm,D_o=420 mm,T=300 KN-m ,G=80 G Pa$

We know that

$\dfrac{\tau}{J}=\dfrac{T}{r}=\dfrac{G\theta}{L}$

J for hollow shaft $J=\dfrac{\pi (D_o^4-D_i^4)}{64}$

(a)

Maximum shear stress $\tau =\dfrac{16T}{\pi Do^3(1-K^4)}$

$K=\dfrac{D_i}{D_o}$ ⇒K=0.83

$\tau =\dfrac{16\times 300\times 1000}{\pi\times 0.42^3(1-.88^4)}$

$\tau=51.55 MPa$

(b)

We know that $\tau \alpha r$

So $\dfrac{\tau_{max}}{\tau}=\dfrac{R_o}{r}$

$\dfrac{51.55}{\tau}=\dfrac{210}{175}$

$\tau=42.95MPa$

(c)

$\dfrac{\tau_{max}}{R_{max}}=\dfrac{G\theta }{L}$

$\dfrac{51.55}{210}=\dfrac{80\times 10^3\theta }{2500}$

$\theta=7.67\times 10^{-3}$ rad.

8 0

4 years ago

In manufacturing a particular set of motor shafts, only shaft diameters of between 38.00 and 37.50 mm are usable. If the process

Masteriza [31]

Answer:

$P(37.5$

And we can find this probability with this difference:

$P(-2.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-2.5$

So then the percentage usable are 94,6%

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the diameters of a population, and for this case we know the distribution for X is given by:

$X \sim N(37.8,0.12)$

Where $\mu=37.8$ and $\sigma=0.12$

We are interested on this probability

$P(37.5$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(37.5$

And we can find this probability with this difference:

$P(-2.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-2.5$

So then the percentage usable are 94,6%

4 0

3 years ago

Using the Breguet range and endurance equation, estimate the amount of kerosene

love history [14]

The amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

<h3>What is Breguet equation?</h3>

Breguet equation is used to determine the range of airplane fly in some specified set of parameters.

$R=\dfrac{h_f}{g}\dfrac{L}{D}\times \eta \ln \left(\dfrac{W_{initial}}{W_{final}}\right)$

Here, (L/D) is lift to drag ratio,<em> g</em> is gravitation acceleration,<em> h </em>is height and <em>W</em> is weight.

The weight of aircraft is 10 metric tons (this is the dry weight that includes passengers and cargo) The distance of 5,000 [km], with velocity at 300 [m/s] from Boston to Los Angeles has to be cover by the airplane.

The initial weight is 10 metric tons or 10000 kg. Thus, the final weight with total fuel burn is,

$W_{final}=W_{initial}-W_{fuel}\\W_{final}=1-\dfrac{W_{fule}}{W_{initial}}$

The lift-to-drag ratio is 15 and the overall efficiency is 0.3, The standard air density at an altitude of approximately 6,000 [m] is half.

Thus, put the values, in above formula,

$5000=\dfrac{6000}{9.81}(15)\times(0.3) \ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)\\$

$\ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)=1.8167\\\ln \left(\dfrac{1}{10000-W_{fuel}}}\right)=1.8167$

Solving this equation, we get,

$W_{fuel}=10000\rm\; kg\\$

Thus, the amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

Learn more about the Breguet equation here:

brainly.com/question/15218094

#SPJ1

7 0

2 years ago

Pie charts should have no more than eight segments. True or False?

Pepsi [2]

Answer:

Explanation:

Pie charts generally should have no more than eight segments.

6 0

3 years ago

Read 2 more answers