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vodka [1.7K]
4 years ago
5

To produce cooling the refrigerant much

Engineering
1 answer:
lawyer [7]4 years ago
7 0
Yes that is correct good job ❤️
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A 2 m3 insulated rigid tank contains 3 kg of nitrogen at 90 kPa. Now work is done on the system until the pressure in the tank r
Nutka1998 [239]

Answer: \Delta S = 1.47kJ/K

Explanation: <u>Entropy</u> is the measure of a system's molecular disorder, i.e, the unuseful work a system does.

The nitrogen gas in the insulated tank can be described as an ideal gas, so it can be used the related formulas.

For the entropy, the ratio of initial and final temperatures is needed and as volume is constant, we use:

\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}

\frac{P_{2}}{P_{1}} =\frac{T_{2}}{T_{1}}

\frac{T_{2}}{T_{1}} =\frac{175}{90}

\frac{T_{2}}{T_{1}} =1.94

<u>Specific</u> <u>Heat</u> is the quantity of heat required to increase the temperature 1 degree of a unit mass of a substance. Specific heat of nitrogen at constant volume is c_{v}= 0.743kJ/kg.K

The change in entropy is calculated by

\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})-Rln(\frac{V_{2}}{V_{1}} )]

For the nitrogen insulated in a rigid tank:

\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})]

Substituing:

\Delta S= 3[0.743ln(1.94)]

\Delta S= 1.47

The entropy change of nitrogen in an insulated rigid tank is 1.47kJ/K

6 0
3 years ago
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