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vlabodo [156]
3 years ago
12

Sasha walk 12 m in 16.8 seconds sam walked 31 m in 46.5 seconds who was the fastest?

Mathematics
2 answers:
irina [24]3 years ago
7 0
Sasha: 16.8 seconds divided by 12 m=1.4 meters per second

Sam:46.5 seconds divided by 31 m=1.5 meters per second
KengaRu [80]3 years ago
4 0

Answer:

Just a bored teen willing to help,

hope you're having a splendiferous day...

Step-by-step explanation:

Sasha: 16.8 seconds÷12 m=1.4 meter per second.

Sam: 46.5 seconds÷31 m=1.5 meter per second.

Sasha walked the fastest.

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Oh ok so square root of 2 is irrational since it goes on and on. square root of 18 is an irrational number too 
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Use the substitution method to solve the system of equations. Write your answer as an order pair. y=x-2 and y=-2x+7
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4 0
3 years ago
A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2
andrey2020 [161]

Answer:

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

Step-by-step explanation:

Consider the provided matrix.

v_1=\begin{bmatrix}-3\\1 \end{bmatrix}

v_2=\begin{bmatrix}-1\\1 \end{bmatrix}

\lambda_1=4, \lambda_2=2

The general solution of the equation x'=Ax

x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}

Substitute the respective values we get:

x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}

Substitute initial condition x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}

\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}

Reduce matrix to reduced row echelon form.

\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}

Therefore, c_1=2.5,c_2=1.5

Thus, the general solution of the equation x'=Ax

x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

6 0
3 years ago
Maria's math test had 25 questions she got 84% correct how many did she get wrong
inysia [295]
\frac{x}{25}=84% \\  \frac{x}{25}=.84 \\ 25( \frac{x}{25})=(.84)(25) \\ x=21
Maria got 21 correct.

Number wrong = Total - Number right
y = 25 - 21
y = 4

Maria got 4 wrong.

Hope this helps!

7 0
3 years ago
Read 2 more answers
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