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3 years ago

Give two other examples each acidic and basic oxids that are not mentioned

Chemistry

2 answers:

alex41 [277]3 years ago

6 0

Hope this helps, have a great day!!

:)

Bingel [31]3 years ago

4 0

Answer:

acidic oxides eg carbon dioxide, sulphur dioxide

basic oxides eg sodium oxide, zinc oxide

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Describe the particles that make up a pure substance

Anni [7]

Answer:

Each element consists of indivisible, minute particles called atoms.

All atoms of a given element are identical.

Atoms of different elements have different masses.

Explanation:

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3 years ago

What flora eat? pliz tell me someone

HACTEHA [7]

Answer:

flora eat food

Explanation:

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3 years ago

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Temperate deciduous trees lose their leaves in Fall. Explain why trees in temperate rainforest and tropical rainforest don’t los

andrey2020 [161]

Answer:

So trees in temperate don't lose their leaves because the weather events aren't harsh enough.

Trees in tropical rainforest don't lose their leaves because they are a different type of tree known as evergreens that are green all year round.

Explanation:

Ok so first we'll define some things

Deciduous Trees= Trees that lose all of their leaves for part of the year.

Trees shed their leaves trees to try and survive harsh weather events.

Temperate deciduous trees lose their leaves in fall to better survive the winter conditions of extreme cold and reduced daylight.

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Broad-leaved trees in tropical rainforests are known evergreen, they are known as this as they are green all year round.

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3 years ago

A student lost part of his lab notebook and didn’t know what the original measure should have been. He knows that he calculated

igor_vitrenko [27]

Answer:

21.1cm or 10.1cm

Explanation:

Since the percent error is 35.5% and the experimental measurement was 15.6cm, the two possible values for the actual measurement are 15.6 plus 35.5% of 15.6 or 15.6 minus 35.5% of 15.6.

This is this:

15.6 + (0.355 x 15.6)
= 15.6 + 5.54
= 21.1cm

Or this:

15.6 - (0.355 x 15.6)
= 15.6 - 5.54
= 10.1cm

6 0

3 years ago

if it takes 54 mL of 0.1 NaOH to neutralize 125 mL of an HCL solution, what is the concentration of HCL?

alexira [117]

Answer:

0.0432 M

Explanation:

We are given;

Volume of NaOH as 54 mL

Molarity of NaOH as 0.1 M

Volume of HCl as 125 mL

We are required to determine the concentration of HCl

Step 1; We write a balanced equation for the reaction between NaOH and HCl

The balanced equation is given by;

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

Step 2: Determine the number of moles of NaOH

Moles = Volume × molarity

Therefore;

Moles of NaOH = 0.054 L × 0.1 M

= 0.0054 Moles

Step 3: We use the mole ratio to determine the moles of HCl

From the equation;

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

Thus; moles of HCl = 0.0054 moles

Step 4: Determine the concentration of HCl

We know that;

Molarity = Moles ÷ Volume

Therefore;

Molarity of HCl = 0.0054 moles ÷ 0.125 L

= 0.0432 M

Therefore, the concentration of HCl is 0.0432 M

6 0

3 years ago