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ratelena [41]
4 years ago
14

Calculate the amount of heat released when one bottle (250 g) of water is cooled from 30oC to 25oC. The specific heat of water i

s (4.186 J/g oC).
Chemistry
1 answer:
Ulleksa [173]4 years ago
3 0

Answer:

The amount of heat released is -5,232.5 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous) is calculated by the expression:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q=?
  • c=4.186 \frac{J}{g*C}
  • m= 250 g
  • Δ=Tfinal - Tinitial= 25°C - 30°C= -5 °C

Replacing:

Q= 4.186 \frac{J}{g*C} *250 g* (-5°C)

Solvng:

Q= -5,232.5 J

The amount of heat released is -5,232.5 J

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y_{O2} =4.3%

Explanation:

The ethanol combustion reaction is:

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1.10(excess)*\frac{3 O_{2}moles}{etOHmole}=3.30\frac{O_{2}moles}{etOHmole}

We would need 3.30 oxygen moles per ethanol mole.

Then we apply the composition relation between O2 and N2 in the feed air:

3.30(O_{2} moles)*\frac{0.79(N_{2} moles)}{0.21(O_{2} moles)}=121.414 (N_{2} moles )

Then calculate the oxygen moles number leaving the reactor, considering that 0.85 ethanol moles react and the stoichiometry of the reaction:

3.30(O_{2} moles)-0.85(etOHmoles)*\frac{3(O_{2} moles)}{1(etOHmoles)} =0.75O_{2} moles

Calculate the number of moles of CO2 and water considering the same:

0.85(etOHmoles)*\frac{3(H_{2}Omoles)}{1(etOHmoles)}=2.55(H_{2}Omoles)

0.85(etOHmoles)*\frac{2(CO_{2}moles)}{1(etOHmoles)}=1.7(CO_{2}moles)

The total number of moles at the reactor output would be:

N=1.7(CO2)+12.414(N2)+2.55(H2O)+0.75(O2)\\ N=17.414(Dry-air-moles)

So, the oxygen mole fraction would be:

y_{O_{2}}=\frac{0.75}{17.414}=0.0430=4.3%

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