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Veronika [31]
4 years ago
11

When Group 1 elements form ions, they?

Chemistry
1 answer:
alexira [117]4 years ago
6 0
Lose an electron to form an ion
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What is a flame,metion two types of flames​
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Answer:

A flame is defined as the gaseous part of the fire which is visible to us. A flame is created due to the high exothermic reaction.

Two types of flames based on the amount of oxygen available are:

  • Non-luminous or blue flame: In this type of flame the amount of oxygen is sufficiently large and it gives blue flame. For example: flame of Gas stove.
  • Luminous flame: In this type of flame, the oxygen availability id not sufficient for the complete combustion and left unburnt carbon particles that forms yellow light flame. For example: kerosene lamp.

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4. -ol

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biology stuff

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Of the following equilibria, only ________ will shift to the right in response to a decrease in volume. N2 (g) + 3H2 (g) 2NH3 (g
igomit [66]

Answer:

Of the following equilibria, only one will shift to the right in response to a decrease in volume.

N_2 (g) + 3H_2 (g)\rightleftharpoons 2NH_3 (g)

On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Decrease the volume

If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. So, the equilibrium will shift in the direction number of gaseous moles are less.

N_2 (g) + 3H_2 (g)\rightleftharpoons 2NH_3 (g)

On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.

2 Fe_2O_3 (s) \rightleftharpoons 4 Fe (s) + 3O_2 (g)

On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

2 SO_3 (g) \rightleftharpoons 2 SO_2 (g) + O_2 (g)

On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

H_2 (g) + Cl_2 (g) \rightleftharpoons 2 HCl (g)

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.

2HI (g) \rightleftharpoons H_2 (g) + I_2 (g)

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.

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So I ordered a moonstone crystal and I was wondering if it’s real and is there anything I need about it??
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