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swat32
2 years ago
12

HELP PLZZ!!!!! a cup of coffee considered _____. a)solute b)precipitation c)solution d)solvent

Chemistry
2 answers:
Sloan [31]2 years ago
3 0
The answer is solvent
arsen [322]2 years ago
3 0
I think it is a solution
As it is MIXTURE of coffee milk and sugar
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Identify two factors that can produce metamorphic rocks
alexdok [17]
Heat & pressure. hope this helps
8 0
3 years ago
Read 2 more answers
The volume of a 2.49 g sample of gas is 752 mL at 1.98 atm and 62 C What is the gas?
creativ13 [48]

Answer:

The volume of a sample of gas (2.49 g) was 752 mL at 1.98 atm and 62∘C 62 ∘ C .

6 0
2 years ago
Based on the shapes of the water drops in part D, how does the attractive force between water and wax compare to the attractive
Minchanka [31]

Answer:

Because the cohesive forces inside the droplets are stronger than the adhesive forces between both the drops and the wax, water does not penetrate waxed surfaces. Because the adhesive forces between the liquid and the glass are stronger than the cohesive forces inside the water, water wets glass and spreads out across it.

Explanation:

EDMENTUM

4 0
1 year ago
A blood sample of 4.01 milliliters is collected from a patient to be analyzed for a platelet count. Human blood should have arou
Harlamova29_29 [7]

Given :

Human blood should have around 1.04 kg/L platelets.

A blood sample of 4.01 milliliters is collected from a patient to be analyzed for a platelet count.

To Find :

The expected mass in grams of platelets in the blood sample.

Solution :

1 L of human blood contains 1.04 kg of platelets.

So, amount of platelets is 1 ml blood is :

=\dfrac{1.04}{1000}\ kg\\\\= \dfrac{1.04\times 1000}{1000}\ gram\\\\= 1.04 \ gram

Mass of platelets in 4.01 ml blood is :

m = 1.04\times 4.01\ gram\\\\m = 4.1704\ gram

Hence, this is the required solution.

3 0
3 years ago
The solubility of calcium sulfate at 30°c is 0.209 g/100 ml solution. calculate its ksp.
inessss [21]
Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.
Balanced chemical reaction (dissociation):
CaSO₄(s) → Ba²⁺(aq) + SO₄²⁻(aq).
m(CaSO₄) = 0.209 g.
n(CaSO₄) = m(CaSO₄) ÷ M(CaSO₄).
n(CaSO₄) = 0.209 g ÷ 136.14 g/mol.
n(CaSO₄) = 0.00153 mol.
s(CaSO₄) = n(CaSO₄) ÷ V(CaSO₄).
s(CaSO₄) = 0.00153 mol ÷ 0.1 L = 0.0153 M.
Ksp = [Ca²⁺] · [SO₄²⁻].
[Ca²⁺] = [SO₄²⁻] = s(CaSO₄).
Ksp = (0.0153 M)² = 2.36·10⁻⁴.
8 0
2 years ago
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