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pantera1 [17]
3 years ago
10

Using the standardized NaOH solution in the previous

Chemistry
2 answers:
geniusboy [140]3 years ago
6 0

Answer:

Using the standardized NaOH solution in the previous question, the titration of 5.00 mL of vinegar required 42.25 mL of NaOH. What is the % of acetic acid in the vinegar? Concentration of NaOH from previous question= 0.0986 M. David C

Explanation:

Eh?

Studentka2010 [4]3 years ago
5 0

Answer: Using the standardized NaOH solution in the previous question, the titration of 5.00 mL of vinegar required 42.25 mL of NaOH. What is the % of acetic acid in the vinegar? Concentration of NaOH from previous question= 0.0986 M. David C.

Explanation:

Please mark as brainliest for me.Thank you so much

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Answer: 15 grams of salt are there in 5 L of solution.

Explanation:

Concentration of a solution is defined as the number of grams of solute dissolved per liter of the solution.

Given : Concentration of solution : 3 g/L

1 Liter of solution contains = 3 gram of salt

Thus 5 L of solution contains = \frac{3g}{1L}\times 5L=15g

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Explanation:

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Calculate the poh of a solution at 25. 0 °C that contains 2. 95 × 10^-12 m hydronium ions.
lapo4ka [179]

The pOH of a solution at 25. 0 °C that contains 2. 95 × 10^-12 M hydronium ions is 0.5.

pH is the concentration of the hydrogen ion released or gained by the species in the solution that depicts the acidity and basicity of the solution.

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Substituting values in the equation:

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14 - pH = pOH

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14 - 13.5 = 0.5 pOH

Therefore, pH is 13.5 and pOH is 0.5.

Learn more about pH and pOH here: brainly.com/question/2947041

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