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elena55 [62]
1 year ago
10

Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or

neutral:(CH₃)₂NH₂ Br
Chemistry
1 answer:
Lelechka [254]1 year ago
4 0

(CH₃)₂NH₂Br is an acidic salt.

<h3>What are acidic salts?</h3>

Neutralization of a strong acid with a weak base gives an acidic salt.

Examples: Ammonium chloride, Copper sulfate, Silver nitrate

<h3>What are basic salts?</h3>

Neutralization of a weak acid with a strong base gives a basic salt.

Examples: Sodium Acetate, Potassium cyanide, Sodium sulfide

<h3>What are neutral salts?</h3>

They are formed by the neutralization of strong acids and strong bases, are called neutral salts because their aqueous solutions are neutral to litmus.  

Examples: The compounds like NaCl, KCl, K2S04, NaN03, KCl03, KClO4 etc. are neutral salts.

To learn more about salts: brainly.com/question/5306491

#SPJ4

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How much energy would it take to heat a section of the copper tubing that weighs about 665.0 g, from 15.71 ∘C to 27.09 ∘C ? Copp
Margarita [4]

Answer:

2914 J

Explanation:

Step 1: Given data

  • Mass of the copper tubing (m): 665.0 g
  • Initial temperature: 15.71 °C
  • Final temperature: 27.09 °C
  • Specific heat of copper (c): 0.3850 J/g.°C

Step 2: Calculate the temperature change

ΔT = 27.09 °C - 15.71 °C = 11.38 °C

Step 3: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.3850 J/g.°C × 665.0 g × 11.38 °C

Q = 2914 J

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FinnZ [79.3K]
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Use the drop-down menus to identify the ocean found at each point on the map. A B C D E those are for the drop-down menu arctic
ivolga24 [154]

Answer:

A-Pacific Ocean

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If a muriatic acid solution has a pH of 2.50, what is the hydronium ion concentration (hydronium ion concentration is also the m
Irina18 [472]

Answer:

  • [H₃O⁺] = 0.032 M

Explanation:

The acidity of a solution is measured by its pH, which is the logarithm of the inverse of the molar concentration of hydronium (H₃O⁺) ions:

  • pH = log 1 / [H₃O⁺] = - log [H₃O⁺]

When you know the pH value you can find hydronium concentration using the antilogaritm function:

pH=-log[H_3O^{+}]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-2.50}\\ \\ {[H_3O^+]}=0.0032

The unit of molar concentration is M.

To prove your answer you can take the logarithm of 0.0316:

  • log (0.0032) ≈ 2.500

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