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elena55 [62]
1 year ago
10

Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or

neutral:(CH₃)₂NH₂ Br
Chemistry
1 answer:
Lelechka [254]1 year ago
4 0

(CH₃)₂NH₂Br is an acidic salt.

<h3>What are acidic salts?</h3>

Neutralization of a strong acid with a weak base gives an acidic salt.

Examples: Ammonium chloride, Copper sulfate, Silver nitrate

<h3>What are basic salts?</h3>

Neutralization of a weak acid with a strong base gives a basic salt.

Examples: Sodium Acetate, Potassium cyanide, Sodium sulfide

<h3>What are neutral salts?</h3>

They are formed by the neutralization of strong acids and strong bases, are called neutral salts because their aqueous solutions are neutral to litmus.  

Examples: The compounds like NaCl, KCl, K2S04, NaN03, KCl03, KClO4 etc. are neutral salts.

To learn more about salts: brainly.com/question/5306491

#SPJ4

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There are many advantages to using nuclear power to generate electricity. There are also many disadvantages. Choose all of the a
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Answer:

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What change in energy occurs when you burn coal or petroleum??
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Chemical energy is converted to thermal energy.

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You leave a piece of bread outside for a few days. It forms green and blue mold. It smells awful. A chemical change has occurred
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For the following reaction, 7.53 grams of benzene (C6H6) are allowed to react with 8.33 grams of oxygen gas. benzene (C6H6) (l)
juin [17]

Answer:

The maximum amount of CO2 that can be formed is 9.15 grams CO2

O2 is the limiting reactant

There will remain 4.82 grams of benzene

Explanation:

Step 1: Data given

Mass of benzene = 7.53 grams

Mass of oxygen gas = 8.33 grams

Molar mass of benzene = 78.11 g/mol

Molar mass oxygen gas = 32.00 g/mol

Step 2: The balanced equation

2C6H6 + 15O2 → 12CO2 + 6H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles C6H6 = 7.53 grams / 78.11 g/mol

Moles C6H6 = 0.0964 moles

Moles O2 = 8.33 grams / 32.00 g/mol

Moles O2 = 0.2603 moles

Step 4: Calculate the limiting reactant

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.2603 moles). Benzene is in excess. there will react 2/15 * 0.2603 = 0.0347 moles

There will remain 0.0964 - 0.0347 = 0.0617 moles benzene

This is 0.0617 moles * 78.11 g/mol = <u>4.82 grams benzene</u>

<u />

Step 5: Calculate moles CO2

For 2 moles benzene we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

For 0.2603 moles O2 we'll have 12/15 * 0.2603 = 0.208 moles CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.208 moles * 44.01 g/mol

<u>Mass CO2 = 9.15 grams</u>

4 0
3 years ago
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