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sukhopar [10]
2 years ago
15

Identify a form of potential energy.

Physics
1 answer:
brilliants [131]2 years ago
5 0

Answer:

Gravitational potential energy (ex. height)

Elastic potential energy (ex. stretched rubber band)

Electrical potential energy (ex. negative charges close together want to repel each other)

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This is a green pigment in chloroplasts that traps light energy from the sun.
vovikov84 [41]
green pigment in the chloroplast is chlorophyll
6 0
3 years ago
if the emission lines in the spectrum of one object are more strongly blueshifted than those from a second object, then the firs
Lelu [443]

Answer:

Toward us faster than the second object

Explanation:

6 0
2 years ago
3. What color of laser light shines through a diffraction grating with a line density of 500 lines/mm if the third maxima from t
mestny [16]

Answer:

Wavelength is 471 nm

Explanation:

Given that,

Lines per unit length of diffraction grating is 500 lines/mm.

The third maxima from the central maxima (m=3) is at an angle of 45°

We need to find the color of laser light shines through a diffraction grating.

The condition for maxima is :

d\sin\theta=m\lambda

d = 1/N, N = number of lines per mm

\lambda=\dfrac{1}{Nm}\sin\theta\\\\\lambda=\dfrac{10^{-3}}{500\times 3}\sin(45)\\\\\lambda=4.31\times 10^{-7}\\\\\text{or}\\\\\lambda=471\ nm

6 0
3 years ago
a projectile is launched from level ground with an initial speed v0 at an angle θ with the horizontal. if air resistance is negl
LekaFEV [45]

The time of flight of the launched particle will be 2v₀ sinθ / g.

<h3>What is kinematics?</h3>

The study of motion without considering the mass and the cause of the motion.

A projectile is launched from level ground with an initial speed v₀ at an angle θ with the horizontal. If air resistance is negligible.

Then the time of flight of the launched particle will be given as,

Determine how long it requires the projectile to reach its highest point in order to calculate the flight duration. Just twice as long as the maximum altitude is the travel time.

\rm v_y = v_{o_y} + a_y t

At maximum height, \rm v_y = 0.

The time to reach maximum height is given as

\rm t_{1/2} = - \dfrac{v_{o_y} }{ a_y}

The time of flight is given as,

\rm t = 2 \times t_{1/2} = - \dfrac{2v_{o_y}}{ a_y}

Substituting in \rm v_{o_y} = v_o \ \sin(\theta ) \ and \ a_y = -g, then we have

The time of flight of the launched particle will be 2v₀ sinθ / g.

More about the kinematics link is given below.

brainly.com/question/7590442

#SPJ4

6 0
1 year ago
A window air conditioner that consumes 2 kW of electricity when running and has a coefficient of performance of 3 is placed in t
finlep [7]

Answer: Q= QH - QL

= W + QL - QL

= W

= 1 kj/8

Explanation:

Since the net rate is positive the room will be heated.

5 0
3 years ago
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