The solution would be like this for this specific problem:
Given:
pH of a 0.55 M hypobromous
acid (HBrO) at 25.0 °C = 4.48
[H+] = 10^-4.48 = 3.31 x
10^-5 M = [BrO-] <span>
Ka = (3.31 x 10^-5)^2 / 0.55 = 2 x 10^-9</span>
To add, Hypobromous Acid does not require acid
adjustment, which is necessary for chlorine-based product and is stable and
effective in pH ranges of 5-9.<span>
</span>Hypobromous Acid combines with organic
compounds to form a bromamine. Chlorine also combines with the same organic
compounds to form a chloramine. <span>It is also
one of the least expensive intervention antimicrobial compounds available.</span>
Answer=C
Mobile electrons bring about high electrical conductivity
Answer:
d
Explanation:
an atom that have bonded is the right answer
Friedel-Crafts alkylation requires dry conditions because AlCl3 may combine with water thereby hindering the reaction.
Friedel-Crafts involves the introduction of an alkyl group into a benzene ring. This occurs by electrophilic substitution of a proton on the aromatic ring with an alkyl group.
The set up must be free from water because water could inactivate the Lewis acid (AlCl3) due to combination of the Lewis acid with water thereby hindering the reaction.
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