Temperature is a measure of thermal energy. Like, how hot or cold something is. When testing a temperature, you would use a <em>thermometer</em>. A thermometer measures how hot or cold something is.
Hope this helps. :)
Mass is often the most common and weight is its close to that but I'd go with mass
Answer:
204.8g
Explanation:
The number of moles of a substance is related to its mass and molecular mass as follows:
mole (n) = mass (m) ÷ molar mass (MM)
According to this question, 3.50 moles of sodium chloride (NaCl) is added to a food.
Molar mass of NaCl = 23 + 35.5
= 58.5g/mol
Using mole = mass/molar mass
Mass = molar mass × mole
Mass = 58.5g/mol × 3.5mol
Mass = 204.75
Mass = 204.8grams.
Therefore, 204.8grams of NaCl or common salt was added to the food.
The chemical equation would be:
2NO(g) + O2(g) --> 2NO2 (g)
<span>At equilibrium state, the partial pressure of the gases would be as follows : </span>
<span>NO = 522 - 2x </span>
<span>O2 = 421 - x </span>
<span>NO2 = 2x </span>
<span>- - - - - - - - - - - - -</span>
<span>943 - x = 748 </span>
<span>x = 195</span>
Calculating for Kp,
<span>Kp = (NO2)^2/ ((NO)^2 * (O2)) </span>
<span>Kp = (2 * 195)^2/ ((522 - 2 * 195)^2 * (421 - 195)) </span>
<span>Kp = 0.0386 </span>
Answer:
-65.897°C.
Explanation:
- Adding solute to water causes depression of the boiling point.
- The depression in freezing point (ΔTf) can be calculated using the relation: <em>ΔTf = Kf.m,</em>
where, ΔTf is the depression in freezing point of chloroform solution.
Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).
m is the molality of the solution (m = 0.51 m).
∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.
∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.
