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EleoNora [17]
3 years ago
11

Solid calcium carbide, CaC2, reacts with water to form an aqueous solution of calcium hydroxide and acetylene gas, C2H2. Express

your answer as a balanced chemical equation. Identify all of the phases in your answer. nothing
Chemistry
1 answer:
Lina20 [59]3 years ago
4 0

Answer:  CaC_2(s)+H_2O(l)\rightarrow Ca(OH)_2(aq)+C_2H_2(g)

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The solutions in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas. Liquids are represented by (l) and gases are represented by (g).

The balanced chemical reaction is:

CaC_2(s)+2H_2O(l)\rightarrow Ca(OH)_2(aq)+C_2H_2(g)

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Explanation:

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Convert 26.02 x 1023 molecules of C2H8 to grams. Round your answer to the hundredths place.
aliina [53]

Answer:

x= 138.24 g

Explanation:

We use the avogradro's number

6.023 x 10^23 molecules -> 1 mol C2H8

26.02 x 10^23 molecules -> x

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x= 4.32 mol C2H8

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4 0
3 years ago
Kemmi Major does some experimental work on the combustion of sucrose: C12H22O11(s) 12 O2(g) → 12 CO2(g) 11 H2O(g) She burns a 0.
Pavlova-9 [17]

Answer: 5.81\times 10^6J/mol

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Heat of combustion is the amount of heat released when 1 mole of the compound is completely burnt in the presence of oxygen.

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To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.05392g}{342g/mol}=1.577\times 10^{-4}moles

Thus 1.577\times 10^{-4}moles of sucrose releases =  916.6 J of heat

1 mole of sucrose releases =\frac{916.6}{1.577\times 10^{-4}}\times 1=5.81\times 10^6J of heat

Thus ∆H value for the combustion reaction is 5.81\times 10^6J/mol

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3 years ago
When the nuclide iron-59 undergoes beta decay: The name of the product nuclide is . The symbol for the product nuclide is .
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Answer:

Explanation:

⁵⁹₂₆Fe --------- ⁰₋₁e + ⁵⁹₂₇Co

Co- 59 is known as Cobalt

its symbol is ⁵⁹₂₇Co

5 0
3 years ago
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