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3 years ago

When a sample of a gas is heated in a sealed, rigid container from 200. K to 400. K, the pressure exerted by the gas is:

1 answer:

5 0

When a sample of a gas is heated in a sealed, rigid container from 200 degree Kelvin to 400 degree Kelvin, the pressure exerted by the gas is increased by a factor 2. Heating any gas actually increases the volume of the gas within a container. As the temperature of the gas rises, the molecules of the gas start moving faster and start striking the walls of the container in which it is kept with more force. The volume of the container tries to expand to accommodate the fast colliding molecules of the gas.

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How many ounces are in a 2-liter of soda? Just out of curiousity?

tamaranim1 [39]

There are 67.6 ounces in a 2-liter soda.

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3 years ago

A balloon contains 0.5 L of air at 101.5 kPa. You squeeze it to a volume of 0.25 L. What is the pressure of air inside the ballo

Igoryamba

The answer would be D. 203kPa

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3 years ago

The following reaction: HF(aq) <--> H+(aq) + F-(aq) has an equilbirum constant (K) value of 7.2 x 10-4. This means that th

andriy [413]

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

<h3>What is the equilibrium constant?</h3>

In a reaction, we can judge using the value of the equilibrium constant weather or not the reaction moves on to completion. If the reaction moves up to completion, it the follows that the value of the equilibrium constant ought to be large.

On the other hand, when we have a case that the equilibrium constant is small and is not so large, then the reaction does not proceed essentially to completion.

Given an equilibrium constant value of 7.2 x 10-4 it is false to say that the reaction proceeds essentially to completion.

Learn more about equilibrium constant:brainly.com/question/10038290

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2 years ago

What are two ways to describe concentration? How do they differ from one another?

adell [148]

Answer:

no .........................

3 0

3 years ago

Read 2 more answers

You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans

OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

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3 years ago