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PtichkaEL [24]
3 years ago
9

A constellation is _______ that forms a pattern resembling animals, mythological characters, or objects.

Physics
2 answers:
andrew11 [14]3 years ago
8 0
C, a group of stars that form patterns in the night sky.
Svetradugi [14.3K]3 years ago
4 0

A constellation is a group of stars.

Since human brains have evolved to look for patterns,
we sometimes seem to see patterns in groups of points. 
Different people make different pictures from the patterns ...
it depends on what they have on their mind.
 
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Chemical weathering may occur because the mineral or rock is exposed to the air. this reaction occurs naturally with some chemic
aliya0001 [1]

Answer: a. oxidation

Explanation:

The weathering is a process through which the large rocks are broken into small rocks or pieces. The weathering can be caused by the physical and chemical agents.

The chemical weathering is a process in which the rock is disintegrated or broken into sub-components by the action of the chemical agents present in the surrounding of rock for example, air, water, acid, and alkali.

The air will cause the oxidation of the rocks. This will cause weathering of rocks as the oxygen will react with the minerals present in rocks making their bonds weak and causes disintegration of rocks.

3 0
3 years ago
"the destructive force of waves is not felt while they are out at sea, in the open ocean, but it is felt when they do what?"
Bond [772]
<span>The destructive force of waves is not felt in open ocean, for example boats far away from the coastline can ofter survive even catastrophic tsunamis. The force is felt and damage is done once the waves reach land, or very shallow water.</span>
7 0
4 years ago
Which is the 2nd closest star to earth??
IgorLugansk [536]

Answer:

Proxima Centauri

Explanation:

U 2 can help me by marking as brainliest........

8 0
3 years ago
Read 2 more answers
Something has a mass of 40 kg and a velocity of 1 m/s
lesantik [10]
  • m=40kg
  • v=1m/s

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2

\\ \sf\Rrightarrow K.E=20J

<h3>Part 2:-</h3>
  • m=80kg

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2

\\ \sf\Rrightarrow K.E=40J

  • Yes
6 0
3 years ago
A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of th
Ber [7]

Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

Electron mobility, u = 3900

Hole mobility, h = 1900

Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)

R = 1 /0.0001831

R = 5461.4964 ohm /cm

5461.4964 / 10000

0.546 ohm / μm

7 0
3 years ago
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