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3 years ago

Serve(s) to increase cellular surface area.

Chemistry

2 answers:

omeli [17]3 years ago

7 0

The answer is microvilli.

Aliun [14]3 years ago

7 0

Microbiology massively increases the cellular surface area

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Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac

GalinKa [24]

<h2>a) The rate at which $NO_2$ is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen $O_2$ is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$ = 0.066 M/s

Rate in terms of disappearance of $O_2$ = $-\frac{1d[O_2]}{dt}$

Rate in terms of appearance of $NO_2$ = $\frac{1d[NO_2]}{2dt}$

1. The rate of formation of $NO_2$

$-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}$

$\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s$

2. The rate of disappearance of $O_2$

$-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}$

$-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

Learn more about rate law

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https://brainly.in/question/1297322

7 0

3 years ago

Ideal He gas expanded at constant pressure of 3 atm until its volume was increased from 9 liters to 15 liters. During this proce

kkurt [141]

Explanation:

The given data is as follows.

P = 3 atm

= $3 atm \times \frac{1.01325 \times 10^{5} Pa}{1 atm}$

= $3.03975 \times 10^{5} Pa$

$V_{1}$ = 9 L = $9 \times 10^{-3} m^{3}$ (as 1 L = 0.001 $m^{3}$ ),

$V_{2}$ = 15 L = $15 \times 10^{-3} m^{3}$

Heat energy = 800 J

As relation between work, pressure and change in volume is as follows.

W = $P \times \Delta V$

or, W = $P \times (V_{2} - V_{1})$

Therefore, putting the given values into the above formula as follows.

W = $P \times (V_{2} - V_{1})$

= $3.03975 \times 10^{5} Pa \times (15 \times 10^{-3} m^{3} - 9 \times 10^{-3} m^{3})$

= 1823.85 Nm

or, = 1823.85 J

As internal energy of the gas $\Delta E$ is as follows.

$\Delta E$ = Q - W

= 800 J - 1823.85 J

= -1023.85 J

Thus, we can conclude that the internal energy change of the given gas is -1023.85 J.

8 0

3 years ago

Noah and Nina are 15 m apart in a closed room. Noah says the same sentence twice. The first time, Nina does not hear the sound,

In-s [12.5K]

The air molecules in the compressions of the second wave are denser, so the sound is louder.

<h3>What is a sound wave?</h3>

Sound waves are longitudinal waves that travel through a medium like air or water.

In a closed room, Noah and Nina are sitting 15 m apart.

As Noah says the same sentence twice, Nina does not hear the sound the first time but she does hear the sentence the second time.

This happens as the air molecules in the compressions of the second wave are denser. As a result, the sound is louder.

The correct option is ''The air molecules in the compressions of the second wave are denser, so the sound is louder''.

Learn more about the sound wave here:

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5 0

2 years ago

I have no idea how to do this help plz!

Wittaler [7]

The answes are
C)
Then it is
)A
Im doing this for class too bruh

8 0

3 years ago

Read 2 more answers

Angiosperms produce brightly colored blooms and sweet-smelling flowers. Why have angiosperms developed these adaptations? A. to

blsea [12.9K]

Answer:

Explanation:

Angiosperms have developed these adaptations because it attracts pollinators which helps the ecosystem grow.

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3 years ago