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alisha [4.7K]
3 years ago
5

Serve(s) to increase cellular surface area.

Chemistry
2 answers:
omeli [17]3 years ago
7 0
The answer is microvilli.
Aliun [14]3 years ago
7 0
Microbiology massively increases the cellular surface area
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Suppose you have been given the task of distilling a mixture of hexane + toluene. Pure hexane has a refractive index of 1.375 an
rosijanka [135]

Answer:

Mole fraction of hexane in your sample is 0,746

Explanation:

Based on the information you can write the following equations:

X + Y = 1 <em>(1)</em>

Where X is mole fraction of hecane and Y is mole fraction of toluene

Also, based on the assumption that the refractive index of the hexane + toluene mixture varies linearly with mole fraction you can write:

1,375X + 1497Y = 1406 <em>(2)</em>

<em></em>

Replacing (1) in (2):

1,375X + 1,497(1-X) = 1,406

1,375X - 1,497X + 1,497 = 1,406

-0,122X = -0,091

X = -0,091/-0,122

X = 0,746

Thus, the <em>mole fraction of hexane in your sample is 0,746</em>

Also you can know the mole fraction of toluene replacing this value in (1):

0,746 - Y = 1

Y = 1-0,746

Y = 0,254

I hope it helps!

4 0
3 years ago
_____ is the state of matter of the sun and stars
Kitty [74]
The answer is C. Gas
5 0
3 years ago
Read 2 more answers
What is the acceleration of the object’s motion? 0.5 m/s2 -0.5 m/s2 2 m/s2 -2 m/s2
djverab [1.8K]

Answer:  -2m/s2

Explanation:

Using the following equation ; acceleration = Change in velocity / time

i.e  a =  v - u / t

where  'a'  = acceleration

              v  = final velocity

              u  =  initial velocity

              t   =  time

Therefore;  from the graph we have acceleration to be, 0 - 6m/s / 3s  = -2m/s2

5 0
4 years ago
Hidróxido de rubidio (1+) formula
Schach [20]

Answer: RbOH

Explanation: i think

4 0
3 years ago
Calcium fluoride (CaF2) has a solubility constant of 3.45 x 10-11
tangare [24]
Ksp=3.45×10⁻¹¹

CaF₂(s) ⇄ Ca²⁺(aq) + 2F⁻(aq)

Ksp=[Ca²⁺][F⁻]²

[Ca²⁺]=C(CaF₂)
[F⁻]=2C(CaF₂)

Ksp=4{C(CaF₂)}³

C(CaF₂)=∛(Ksp/4)

C(CaF₂)=∛(3.45×10⁻¹¹/4)=2.05×10⁻⁴ mol/L

2.05×10⁻⁴ M
3 0
3 years ago
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